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3 years ago

Three candy bars cost $3.81 at this rate how much does 7 candy bars cost

Mathematics

2 answers:

Mila [183]3 years ago

8 0

Answer:

$8.89

Step-by-step explanation:

one is 1.27 so multiply that by 7 and you get $8.89

Charra [1.4K]3 years ago

4 0

Answer:

3.81 ÷3 = 1.27

1 27×7 = 8.89

7 candy bars cost $8.89

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Factorise the following algebraic expressions completely a. y4 −81 . x2 +10x +24

Ludmilka [50]

$y^4-81=(y^2-9)(y^2+9)=(y-3)(y+3)(y^2+9)\\\\
x^2 +10x +24 =x^2+10x+25-1=(x+5)^2-1=(x+5-1)(x+5+1)=(x+4)(x+6)$

3 0

3 years ago

Y∝1√x<br> If <br> y=7 when x=64<br> find, <br> x when y=8

Taya2010 [7]

Answer:

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Step-by-step explanation:

3 0

3 years ago

Angela makes a pillow in the shape of a wedge to use for watching TV. The pillow is filled with 121212 feet^3 3 start superscrip

Dahasolnce [82]

Answer:

The question is incomplete, the complete question is Angela makes a pillow in the shape of a wedge to use for watching TV. The pillow is filled with 12 ft³ of fluffy material. The base is 3 ft, the height is 2 ft, what is the length of the pillow?

The length of the pillow is 4 feet

Step-by-step explanation:

The formula of the volume of the wedge is $V=\frac{1}{2}bhl$ , where

b is the base of it
h is the height of it
l is the length of it

∵ The pillow in the shape of a wedge

∵ The pillow is filled with 12 ft³ of fluffy material

∴ The volume of the wedge = 12 ft³

∵ The base = 3 feet

∵ The height = 2 feet

- Use the formula of the volume above to find its length

∵ $V=\frac{1}{2}(2)(3)l$

∴ V = 3 l

∵ V = 12 ft³

- Equate 3 l by 12

∴ 3 l = 12

- Divide both sides by 3

∴ l = 4 feet

∴ The length of the pillow is 4 feet

8 0

3 years ago

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

Lelechka [254]

Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

$f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)$

So we can say that

$a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}$

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

$(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab$

and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

$(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab$

it comes

$x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}$

multiply by 3

$3x^2-20x+2*16+5=3x^2-20x+37$

4 0

3 years ago

Lionel wanted to share 4 muffins with his 5 friends. He separated the muffins into 6 equal parts

Alinara [238K]

Answer:

24 muffins, each friend gets 4. There are 4 remaining

Step-by-step explanation:

4 0

3 years ago