Answer:
1) R1 + ((R2 × R3)/(R2 + R3))
2) 0.5 A
3) 3.6 V
Explanation:
1) We can see that resistors R2 and R3 are in parallel.
Formula for sum of parallel resistors; 1/Rt = 1/R2 + 1/R3
Making Rt the subject gives;
Rt = (R2 × R3)/(R2 + R3)
Now, Resistor R1 is in series with this sum of R2 and R3. Thus;
Total resistance of circuit = R1 + ((R2 × R3)/(R2 + R3))
2) R_total = R1 + ((R2 × R3)/(R2 + R3))
We are given;
R1 = 7.2 Ω
R2 = 8 Ω
R3 = 12 Ω
R_total = 7.2 + ((8 × 12)/(8 + 12))
R_total = 7.2 + 4.8
R_total = 12 Ω
Formula for current is;
I = V/R
I = 6/12
I = 0.5 A
3) since current through the circuit is 0.5 and R1 is 7.2 Ω.
Thus, potential difference through R1 is;
V = IR = 0.5 × 7.2 = 3.6 V
Answer:
Electrons
Explanation:
Only Protons and Neutrons are found in the nucleus
Answer:
Option E
Explanation:
- The path of the Pluto is not in line with the rest of the eight planets of our solar system whereas it is more inclined, i.e., inclination of to the ecliptic.
- The orbit of the pluto is more elliptical and more oval in shape than any other planet as a result of the cooling and refreezing of the gases.
Ecliptic:
It is a term used for the imaginary path of the sun annually.
It also represents the line along which the occurrence of the eclipses take place.
Answer:
c
Explanation:
electronic balance must always be at zero to prevent errors in measured value
Answer:
The net force acting on the otter along the incline is 13.96 N.
Explanation:
It is given that,
Mass of the otter, m = 2 kg
Distance covered by otter, d = 85 cm = 0.85 m
It takes 0.5 seconds.
We need to find the net force acts on the otter along the incline. If a is the acceleration of the otter. It can be calculated using second equation of motion as :
Here, u = 0 (at rest)
The net force acting on the otter along the incline is given by :
F = ma
F = 13.6 N
So, the net force acting on the otter along the incline is 13.96 N. Hence, this is the required solution.