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Alexeev081 [22]
3 years ago
11

Use induction to prove that 2 divides n^2 n whenever n is a positive integer

Mathematics
1 answer:
andrey2020 [161]3 years ago
5 0

Answer:

that's wrong

Step-by-step explanation:

for n = 1

n^(2n)=1²=1

and 2 doesnt devide 1

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Write this equation in slope intercept form 3x+2y=4
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y=-3/2x+2

Step-by-step explanation:

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!! AP CALCULUS AB !!<br> find the limit of [(secx*sinx) + (cscx*cosx)]/(3secx) as x approaches 3pi/2
uysha [10]

f(x)= \frac{\frac{\sin{x}}{\cos{x}}+\frac{\cos{x}}{\sin{x}}}{3\sec{x}}

\frac{\frac{\sin{x}}{\cos{x}}+\frac{\cos{x}}{\sin{x}}}{3\sec{x}} \implies \\ \frac{\sin^2{x}+\cos^2{x}}{\sin{x}\cos{x}}\frac{\cos{x}}{3}\implies \\\frac{1}{\sin{x}\cos{x}}*\frac{\cos{x}}{3}\implies \\ \frac{1}{3\sin{x}}

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3 years ago
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3 years ago
I need help on this one thanks.
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4 0
3 years ago
7 people show up to apply for jobs as cashiers at a discount store. Among 7 applicants, four are females. What is the probabilit
Lerok [7]

Answer:

11.43% probability that the first three lined up in the interview are all females if the order is chosen at random

Step-by-step explanation:

Initially, there are 7 applicants, 4 of which are female. So the probability of the first person lined up in the interview being a female is 4/7.

Now we suppose that a female has been chosen, which means that there are 6 applicants, 3 of which are female. So the probability of the second person lined up in the interview being a female is 3/6.

We suppose that the second choice was also a female. Now there are 5 applicants, 2 of which are female. So the probability of the third person lined up in the interview being a female is 2/5.

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P = \frac{4}{7}*\frac{3}{6}*\frac{2}{5} = 0.1143

11.43% probability that the first three lined up in the interview are all females if the order is chosen at random

5 0
3 years ago
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