The answer is the 4th option because they don't use oxygen, that's what they produce
Ur answer is 3 and i'm sure of it
Answer:
the rate of heat transfer after the system achieves steady state is -3.36 kW
Explanation:
Given the data in the question;
mass of water m = 50 kg
N = 300 rpm
Torque T = 0.1 kNm
V = 110 V
I = 2 A
Electric work supplied W₁ = PV = 2 × 110 = 220 W = 0.22 kW
Now, work supplied by paddle wheel W₂ is;
W₂ = 2πNT/60
W₂ = (2π × 0.1 × 300) / 60
W₂ = 188.495559 / 60
W₂ = 3.14 kW
So the total work will be;
W = 0.22 + 3.14
W = 3.36 kW
Hence total work done on the system is 3.36 kW.
At steady state, the properties of the system does not change so the heat transfer will be 3.36 KW.
The heat will be rejected by the system so the sign of heat will be negative.
i.e Q = -3.36 kW
Therefore, the rate of heat transfer after the system achieves steady state is -3.36 kW
Power = (voltage) x (current)
If the camcorder is USING 14 watts of electrical power right now, then . . .
14 watts = (2 volts) x (current)
Divide each side by (2 volts):
Current = (14 watts) / (2 volts)
Current = (14 V-A) / (2 V)
<em>Current = 7 Amperes</em>
