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sveta [45]
3 years ago
14

A student drops a ball from a height of 97.0m. If the ball increases speed at a uniform rate of 10.0m/s^2, determine all unknown

s and answer the following questions.
How long did the ball remain in the air?

What was the balls speed just before striking the ground?
Physics
1 answer:
Fudgin [204]3 years ago
6 0

given :

h = 97.0 m

g = 10.0m/s²

find:

a) t

b) Vt

solutions:

a)

h = ½.g.t²

97 = ½. 10.t²

97 = 5.t²

t² = 97/5 = 19.4

t =√19.4 = 4.4

the ball will remain in the air

for 4.4 s

b)

Vt = g. t

= 10 × 4,4

= 44 m/s

the balls speed before striking the ground

= 44 m/s

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meriva

Answer:

Explanation:

a )

initial velocity u = 45 m/s

acceleration a = - 5 m/s²

final velocity v = 0

v = u - at

0 = 45 - 5 t

t = 9 s

b )

s = ut - 1/2 at²

= 45 x 9 - .5 x5x 9²

405 - 202.5

202.5 m

2 )

a )

s = ut + 1/2 a t²

u = 0

s = 1/2 at²

= .5 x 9.54 x 6.5²

= 201.5 m

b )

v = u + at

= 0 + 9.54 x 6.5

= 62.01 m / s

3

a )

acceleration = (v - u) / t

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= - 3.33 m /s²

b )

v² = u² - 2 a s

34² = 42² - 2 x 3.33² s

s = 27.41 m

c )

Average velocity

Total displacement / time

= 27.41 / 2.4

= 11.42 m /s

4 )

a )

v = u + at

v = 0 + 3 x 4

= 12 m /s

b )

s = ut + 1/2 a t²

= o + .5 x 3 x 4²

= 24 m

8 0
3 years ago
Which simple machines make up a wheel barrow
7nadin3 [17]

Answer:

a lever and a wheel and axle (i guess)

Explanation:

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4 0
3 years ago
An ideal gas is enclosed in a piston, and 1600 J of work is done on the gas. As this happens, the internal energy of the gas inc
Phantasy [73]

Answer:

- 1100 J heat flows out

Explanation:

dW = - 1600 J (as work is done on the gas)

dU = 500 J

dQ = ?

According to the first law of thermodynamics

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3 0
3 years ago
A 5 meter long ladder leans against a wall. The bottom of the ladder slides away from the wall at the constant rate of 1 3 m/s.
Oksana_A [137]

Answer:9.75 m/s

Explanation:

Given

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From diagram

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at x=3

y^2=25-9=16

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2x\frac{\mathrm{d} x}{\mathrm{d} t}+2y\frac{\mathrm{d} y}{\mathrm{d} t}=0

x\frac{\mathrm{d} x}{\mathrm{d} t}=-y\frac{\mathrm{d} y}{\mathrm{d} t}

3\times 13=-4\times \frac{\mathrm{d} y}{\mathrm{d} t}

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5 0
3 years ago
The surface temperature of our sun is about 5800 K, and the peak of its intensity curve is in the middle of the visible spectrum
amm1812

Explanation:

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I should say that the temperature of the star should be close to that of the sun because of the similarity in the intensity curves

3 0
2 years ago
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