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sveta [45]
3 years ago
14

A student drops a ball from a height of 97.0m. If the ball increases speed at a uniform rate of 10.0m/s^2, determine all unknown

s and answer the following questions.
How long did the ball remain in the air?

What was the balls speed just before striking the ground?
Physics
1 answer:
Fudgin [204]3 years ago
6 0

given :

h = 97.0 m

g = 10.0m/s²

find:

a) t

b) Vt

solutions:

a)

h = ½.g.t²

97 = ½. 10.t²

97 = 5.t²

t² = 97/5 = 19.4

t =√19.4 = 4.4

the ball will remain in the air

for 4.4 s

b)

Vt = g. t

= 10 × 4,4

= 44 m/s

the balls speed before striking the ground

= 44 m/s

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Why is the density of iron higher than the density of oxygen?
pentagon [3]

Answer:

Density of iron is higher than the density of oxygen because iron is solid and the particles in it are very compact but oxygen is not dense as it is gas and particles in it are loosely packed.

7 0
3 years ago
An astronaut who is repairing the outside of her spaceship accidentally pushes away a 92.9 cm long steel rod, which flies off at
DiKsa [7]

Answer:

V = 0.0723 volts = 72.3 milivolts

Explanation:

The emf induced in the rod is the motional emf due to the magnetic field. This motional emf can be calculated by the following formula:

EMF = V = vBl Sin\theta

where,

V = Motional EMF = ?

v = speed of rod = 12.5 m/s

B = Magnetic Field = 6.23 mT = 0.00623 T

l = Length of rod = 92.9 cm = 0.929 m

θ = angle between v and B = 90°

Therefore,

V = (12.5\ m/s)(0.00623\ T)(0.929\ m)Sin\ 90^o\\

<u>V = 0.0723 volts = 72.3 milivolts</u>

7 0
3 years ago
Can you help please !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
topjm [15]
A deep zone.........................

4 0
3 years ago
A horse is pulling 53.0 kg plow forward while the ground exerts a 275 N force, and the plow accelerates at 0.222 m/s^2. what is
JulsSmile [24]
Answer:
Magnitude of force the ground exerts on the plow = 263.234 N

Explanation:
Magnitude of force the ground exerts on the plow = Fground - Fplow
We are given that:
Fgound = 275 N
We will now calculate Fplow as follows:
Fplow = mass of horse * acceleration of plow
Fplow = 53 * 0.222
Fplow = 11.766 N

Now, substitute in the above equation to get magnitude of force the ground exerts on the plow as follows:
Magnitude of force the ground exerts on the plow = Fground - Fplow
Magnitude of force the ground exerts on the plow = 275 - 11.766
Magnitude of force the ground exerts on the plow = 263.234 N

Hope this helps :)
3 0
3 years ago
As a dilligent physics student, you carry out physics experiments at every opportunity. At this opportunity, you carry a 1.39-m-
grin007 [14]

Answer:

The strength of magnetic field is 6.21 \times 10^{-5} T

Explanation:

Given:

Length of rod l = 1.39 m

Velocity v = 3.37 \frac{m}{s}

Induced emf = 0.291 \times 10^{-3} V

According to the faraday's law

Induced emf = Blv

We have to find strength of the magnetic field,

   B = \frac{0.291 \times 10^{-3} }{1.39 \times3.37}

   B = 6.21 \times 10^{-5} T

Therefore, the strength of magnetic field is 6.21 \times 10^{-5} T

7 0
4 years ago
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