All categories

3 years ago

Data: While completing the virtual lab complete the data table below

Chemistry

1 answer:

12345 [234]3 years ago

8 0

Answer:

We are not able to answer this question without the data.

Explanation:

Please provide weights of each item. Should give given if you are doing a virtual lab.

You might be interested in

How many neutrons does an element have if its atomic number is 60 and its mass number is 157? Your Answe

nexus9112 [7]

Subtract the mass number which is 157 from your atomic number which is 60. 157-60=97 neutrons.

3 0

3 years ago

A meteor is moving 468 km per minute traveling in a south-to-north direction passed near Earth in 2013. Does this statement desc

HACTEHA [7]

Answer:

it's describes the velocity. since a direction was specifically given, that means it is displacement, and displacement is to velocity while distance is to speed

3 0

3 years ago

Read 2 more answers

Which graph best shows an inverse relationship?

Ghella [55]

The graphs can be described as

So in case of inverse relationship we will obtain a curve not straight line

3 0

4 years ago

Read 2 more answers

In a mixture of n2 and o2 gases, the mol fraction of n2 is found to be 0.700. the total pressure of the mixture is 1.42 atm. wha

vova2212 [387]

Easy the partial pressure is the 0.9883 as the linguistic compound of the average element of the shell is the same as the boron

8 0

3 years ago

What is the ionic equation for the following<br> 2FeCl(aq)<br> 3Mg(s)<br> 3MgCl(aq)<br> 2Fe(s)

amid [387]

Answer : The net ionic equation will be,

$2Fe^{3+}(aq)+3Mg(s)\rightarrow 3Mg^{2+}(aq)+2Fe(s)$

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,

$2FeCl_3(aq)+3Mg(s)\rightarrow 3MgCl_2(aq)+2Fe(s)$

The ionic equation in separated aqueous solution will be,

$2Fe^{3+}(aq)+6Cl^{-}(aq)+3Mg(s)\rightarrow 3Mg^{2+}(aq)+6Cl^{-}(aq)+2Fe(s)$

In this equation, $Cl^{-}$ is the spectator ion.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$2Fe^{3+}(aq)+3Mg(s)\rightarrow 3Mg^{2+}(aq)+2Fe(s)$

7 0

3 years ago