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Reika [66]
2 years ago
11

given that the 180N weight causes a total extension of 30cm ,determine the spring constant of each spring (the weight of each sp

ring is neglible)​
Physics
1 answer:
IrinaK [193]2 years ago
8 0

Answer:600N/m

Explanation:  Given ;

                       Applied force(F) = 180N

                      Total extension (l) = 30cm =0.30m

                       Spring constant(K) =?

                       From Hooke's law

                         F= kx

                        therefore k= F/x

                                  k = 180N/0.3m

                                    600N/m  

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Explanation :

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3 years ago
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This is a great problem if you like getting tied up in knots
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I found that it makes the problem a lot easier if I give the objects some
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Let the mass of Mass of Object 5 be 20 clods .

Then . . .

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-- The mass of Object 4 is half of the mass of Object 5 = 10 clods.
and
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So now, here are the masses:

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Object #2 . . . . . 40 clods
Object #3 . . . . . 5 clods
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Choice-B.
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Choice-C.
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Choice-D.
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Can't be.
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Conclusion:
If the DISTANCE is the same for all the tests, then Choice-C is
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5 0
3 years ago
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