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ratelena [41]
3 years ago
5

The same 100-cm 3 lead block is carefully submerged in a container of mercury. One cm 3 of

Physics
1 answer:
omeli [17]3 years ago
8 0

Answer:

100cm^3

Explanation:

Using the Displacement \ Method:-

If a solid mass of a known volume is submerged in a container of a fluid, the volume of the fluid displaced is equal to the volume of the solid mass.

Hence volume of mercury displaced is 100cm^3

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Why is pluto not a planet?
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Pluto revolves around a star instead of our SUN. So, it's an "Exo-planet" rather than a Planet. It has declared in 2006 by the scientists.

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What do these letters stand for<br> P=mv
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Answer:

The equation for momentum of a piece of matter.

In either case, the momentum would be less than a linebacker hitting you at full speed. The equation for momentum is written: p = mv where p stands for momentum. That is, mass times velocity equals momentum.

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4 0
2 years ago
To which group/family does each of these belong? A. Sulfur _________ B. Sodium _________ C. Argon _________ D. Silicon _________
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A. Sulfur _________ group 16 chalcogens

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7 0
2 years ago
Two cyclists start on a race between points A and D on two different routes. Cyclist X takes the route passing through the equid
ollegr [7]
The displacement is the shortest distance between two points, which is 546.41. The displacement for both is 546.41 meters

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8 0
3 years ago
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A student throws a rock horizontally from the edge of a cliff that is 20 m high. The rock has an initial speed on 10 m/s. If air
fiasKO [112]

The distance of the rock from the base of the cliff is C) 20 m

Explanation:

The motion of the rock in this problem is a projectile motion, which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction

We start by analyzing the vertical motion to find the time of flight of the rock (the time it takes to reach the ground). We can do it by using the suvat equation:

s=u_y t+\frac{1}{2}at^2

where, taking downward as positive direction,

s = 20 m is the vertical displacement of the rock

u_y=0 is the initial vertical velocity

t is the time of flight

a=g=9.8 m/s^2 is the acceleration of gravity

Solving for t,

t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(20)}{9.8}}=2.02 s

Now we can analzye the horizontal motion: the rock moves horizontally with a constant velocity of

v_x = 10 m/s

Therefore, the horizontal distance covered after a time t is

d=v_x t

and substituting t = 2.02 s, we find the final distance of the rock from the base of the cliff:

d=(10)(2.02)=20 m

Learn more about projectile motion:

brainly.com/question/8751410

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