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Allushta [10]
3 years ago
9

Can someone answer all please.

Chemistry
1 answer:
boyakko [2]3 years ago
8 0

Answer:

poszukaj w necie , proszę a nie prosisz innych o gotowca

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Part A
Elden [556K]

Answer:

ΔG° = -5.4 kJ/mol

ΔG = 873.2 J/mol = 0.873 kJ /mol

Explanation:

Step 1: Data given

ΔG (NO2) = 51.84 kJ/mol

ΔG (N2O4)  = 98.28 kJ/mol

Step 2:

ΔG = ΔG° + RT ln Q

⇒with Q = the reaction quatient

⇒with T = the temperature = 298 K

⇒with R = 8.314 J / mol*K

⇒with ΔG° = ΔG° (N2O4) - 2*ΔG°(NO2 )

⇒ ΔG° = 98.28 kJ/mol - 2* 51.84  kJ/mol

⇒ ΔG° = -5.4 kJ/mol

Part B

ΔG =  ΔG° =RT ln Q

⇒with G° = -5.4 kj/mol = -5400 j/mol

⇒ with R = 8.314 J/K*mol

⇒with T = 298 K

⇒with Q = p(N2O4)/ [ p(NO2) ]² = 1.63/0.36² = 12.577

ΔG = -5400 + 8.314 * 298 * ln(12.577)

ΔG = -5400 + 8.314 * 298 * 2.532

ΔG = 873.2 J/mol = 0.873 kJ/mol

3 0
3 years ago
What is the oxidation state of an individual phosphorus atom in P O 3 3−?
Tju [1.3M]
-3 - 3(-2) = +3
___________________
4 0
3 years ago
ALUMINUM (AI)<br> + NITRATE (NO3)
anzhelika [568]

Answer:

Al(No3)3

Explanation:

hope this is correct....

7 0
2 years ago
This table resembles a condensed version of the modern periodic table. Using the full periodic table as a reference, type the sy
Mekhanik [1.2K]

re write the question.

Explanation:

it seems incomplete.

5 0
2 years ago
Carbon-14 has a half-life of 5,730 years. It is used in "carbon dating" to determine the age of once living organisms. How much
Nookie1986 [14]

Answer:

18 grams

Explanation:

Because 17,190 yrs divided by the amount of years it takes for a half-life to occur is 3. So 3 half life’s happen, so you divide 144/2 once, equaling 72. You divide 72/2 again (another half-life) and you get 36. You then calculate the third half life by dividing 36/2 which equals 18 grams.

7 0
2 years ago
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