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marissa [1.9K]
3 years ago
13

Evaluate 3(3M + N) if possible.

Mathematics
1 answer:
IRISSAK [1]3 years ago
4 0

Answer:

Step-by-step explanation:

3M =  3\left[\begin{array}{ccc}3&2\\0&1\\1&3\end{array}\right]\\\\\\=\left[\begin{array}{cc}3*3&3*2&\\0*3&1*3&\\1*3&3*3&\end{array}\right]\\\\=\left[\begin{array}{cc}9&6&\\0&3&\\3&9&\end{array}\right]

3M + N = \left[\begin{array}{cc}9+1&6+2&\\0+3&3+4&\\3+5&9+6&\end{array}\right]\\\\\\= \left[\begin{array}{cc}10&8&\\3&7&\\8&15&\end{array}\right]

3(3M + N) = \left[\begin{array}{cc}3*10&3*8&\\3*3&3*7&\\8*3&15*3&\end{array}\right]\\\\\\=\left[\begin{array}{cc}30&24&\\9&21&\\24&45&\end{array}\right]

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                   \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

            <em>Find the equation of the line passing through (4, 5) and parallel to </em>

<em>                 3x-2y=4.</em>

<em />

<em>  </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

First of all, We need to convert this equation from standard form (ax+by=c) into slope-intercept form (y=mx+b).

\rightarrow First, add 2y on both sides:-

                            \Large\textsf{3x+2y=4}

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                  \Large\textsf{2y=-3x+4}

\rightarrow Divide by 2 on both sides

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\rule{300}{3}

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Remember, if lines are parallel to each other, then their slope's the same.

So the slope of the line that's parallel to the line whose equation we just found, is

\Large\text{$-\displaystyle\frac{3}{2}$}

Now let's write the equation in point-slope form:-

\hookrightarrow\sf{y-y_1=m(x-x_1)}

Replace numbers with letters, as follows:-

\sf{y-5=-\displaystyle\frac{3}{2} (x-4)}

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Multiply -3/2 times x and -4:-

\hookrightarrow\sf{y-5=-\displaystyle\frac{3}{2} x-6}

Now, Add 5 on both sides:-

\hookrightarrow\sf{y=\displaystyle\frac{3}{2} x+1}

\Uparrow\sf{Our\:equation\:in\:slope\;intercept\;form}

<h3>Good luck with your studies.</h3>

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\rule{300}{1}

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