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Anni [7]
2 years ago
6

Identify the relative minimum of this even function. A) No relative minimum exists for this function. B) The relative minimum is

approximately 0 when x = 0. C) The relative minimum is approximately 1.5 when x ≈ -0.8 or 0.8. D) The relative minimum is approximately -1.7 when x ≈ -3.3 or 3.3
Mathematics
2 answers:
S_A_V [24]2 years ago
6 0

Answer:

option d will be the correct answer

NikAS [45]2 years ago
6 0

Answer:

Option D.....

Step-by-step explanation:

............

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Find the value of c. 64 32 5c+2 C​
Dmitry [639]

Answer:

c = 6

Step-by-step explanation:

(I'm going to call the unidentified inner angle Henry, 'kay?)

First, we need to find Henry.

64 + Henry = 180

(64 - 64) + Henry = (180 - 64)

Henry = 116

Now to c.

Henry + 32 + 5c + 2 = 180

(116 + 32 + 2) + 5c = 180

(150 - 150) + 5c = (180 - 150)

5c/5 = 30/5

c = 6

5 0
3 years ago
A right triangle with side legs of length 13 and 12 what is the value of x enter your answer in the box ​
Y_Kistochka [10]

Step-by-step explanation:

x =  \sqrt{ {12}^{2} +  {13}^{2}  }  \\  = \sqrt{ 144 +  169  }   \\  =  \sqrt{313}  \\  = 17.69 \\

4 0
3 years ago
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Whats the range and domain
Monica [59]

Answer:

the picture wont show up for me sry

Step-by-step explanation:

5 0
2 years ago
he puppy weighed 2 pounds when it was born. He has gained weight, but still weighs less than 11 pounds. How much weight could he
Vikentia [17]

Answer:

n=9

Step-by-step explanation:

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4 0
3 years ago
A recent study from the University of Virginia looked at the effectiveness of an online sleep therapy program in treating insomn
Ludmilka [50]

Answer:

1. The 99% confidence interval for the difference in average is -6.47377 < μ₁ - μ₂ < -11.34623

2. The possible issues in the calculations includes;

a. The confidence level used in the confidence interval can influence the result of the confidence interval observed

b. The sample size is small

Step-by-step explanation:

1. The number of adults with insomnia in the sample = 45

The number of adults that participated in the therapy, n₁ = 22

The number of candidates that served as control group, n₂ = 23

The average score for the for the 22 participants of the program, \overline x_1 = 6.59

The standard deviation for the 22 participants of the program, s₁ = 4.10

The average score for the for the 23 subjects in the control group, \overline x_2 = 15.50

The standard deviation for the 23 subjects in the control group, s₂ = 5.34

The confidence interval for unknown standard deviation, σ, is given by the following expression;

\left (\bar{x}_{1}- \bar{x}_{2}  \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}

α = 1 - 0.99 = 0.01

α/2 = 0.005

The degrees of freedom, df = 22 - 1 = 21

t_{\alpha /2} = t_{0.005, \, 21} = 1.721

Therefore, we have;

\left (6.59- 15.5  \right )\pm1.721 \cdot \sqrt{\dfrac{4.10^{2}}{22}+\dfrac{5.34^{2}}{23}}

The 99% confidence interval for the difference in average is therefore given as follows;

-6.47377 < μ₁ - μ₂ < -11.34623

Therefore, there is considerable evidence that the participants in the survey  had lower average score than the subjects in the control group

2. The possible issues in the calculations are;

a. The confidence level used in the confidence interval can influence the result of the confidence interval observed

b. The sample size is small

5 0
2 years ago
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