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azamat
3 years ago
6

Which percent is equivalent to 12/25​

Mathematics
2 answers:
Norma-Jean [14]3 years ago
5 0

Answer:

48%

Step-by-step explanation:

1. Change 12/25 to a fraction with a denominator of 100

25 x 4=100

12 x 4=48

2. Find the percent

48/100= 48%

svetoff [14.1K]3 years ago
4 0

Answer:

48 percent

Step-by-step explanation:

12 divided by 25 gets you .48 which can be expressed as 48%

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For parts a and bâ, use technology to estimate the following. âa) The critical value of t for a 90â% confidence interval with df
rjkz [21]

Answer:

a) For the 90% confidence interval the value of \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

t_{\alpha/2} =\pm 2.35

b) For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

t_{\alpha/2} =\pm 2.62

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.  

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

Part a

For the 90% confidence interval the value of \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

t_{\alpha/2} =\pm 2.35

Part b

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

t_{\alpha/2} =\pm 2.62

3 0
3 years ago
alabama power came by my house that i just bought and installed a new wire support for one of the telephone poles on the propert
PolarNik [594]

Answer:

30 feets

Step-by-step explanation:

subtrqct 55-25 = 30

8 0
2 years ago
Point A is on a number line halfway between −17−17 and 55. Point B is halfway between point A and 0. What integer does the point
julia-pushkina [17]
Find A first by using formula: (a+b)/2= midpoint
so: A = [(-17)+(55)]/2
         = 36

Now find B using midpoint formula:
B: (a+b)/2 
=36+0/2
=18
6 0
3 years ago
Five out of 35 books are red. write the ratio of red books to total books in THREE different forms.
Serga [27]

Answer:

1:7, 1/7, 1 to 7

Step-by-step explanation:

5/35 = 1/7

5 0
3 years ago
Read 2 more answers
What is the equation of the line that passes through the point (-5,2 ) and has the slope of -2/5
valina [46]

Answer:

y = -2/5x + 2

Step-by-step explanation:

8 0
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