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Vladimir79 [104]
3 years ago
8

Difference between of echo and reverberation​

Physics
1 answer:
KiRa [710]3 years ago
5 0

Answer:

A difference between of echo and reverberation​  is described below in details.

Explanation:

Here's a piece of immediate information: An echo is an individual consideration of a soundwave off a horizon exterior. Reverberation is the consideration of sound waves generated by the superposition of the before-mentioned echoes. ... A reverberation can happen when a sound wave is displayed off a nearby covering.

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A small metal ball with a mass of m = 62.0 g is attached to a string of length l = 1.85 m. It is held at an angle of θ = 48.5° w
notka56 [123]

The distance x will the ball land after flies off with a horizontal initial velocity  is 3.0635 m.

<h3>What is mechanical energy?</h3>

The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

A small metal ball with a mass of m = 62.0 g is attached to a string of length l = 1.85 m. It is held at an angle of θ = 48.5° with respect to the vertical.

The ball is then released. When the rope is vertical, the ball collides head-on and perfectly elastically with an identical ball originally at rest. This second ball flies off with a horizontal initial velocity from a height of h = 3.76 m, and then later it hits the ground.

The conservation of energy principle states that total mechanical energy remains conserved in all situations where there is no external force acting on the system.

Kinetic energy  = Potential energy

1/2 mv² =mgh₁

The velocity at the bottom, when the height h = 5m, is

v= √2gh₁...................(1)

The vertical height h₁ = l- lcosθ

h₁ = l- lcosθ

h₁ = 1.85 - 1.85cos48.5°

h₁ =0.6241 m

Putting the values in equation (1), we get

v = √2x 9.81 x0.6241

v = 3.499 m/s

The horizontal distance traveled is

x = vt

x = v x √2h/g

Plug the values, we get

x =  3.499 x √2x3.76 / 9.81

x = 3.0635 m

Thus, the horizontal distance ball travels is  3.0635 m.

Learn more about mechanical energy.

brainly.com/question/13552918

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6 0
2 years ago
What's the difference between sound waves and pressure waves?
Yuliya22 [10]

Answer:

Since a sound wave consists of a repeating pattern of high pressure moving through a medium it is sometimes referred to as a pressure wave

Explanation:

Since a sound wave consists of a repeating pattern of high pressure moving through a medium it is sometimes referred to as a pressure wave

5 0
3 years ago
Read 2 more answers
A 25-g string is stretched with a tension of 43 N between two fixed points 12 m apart. What is the frequency of the second harmo
Svetllana [295]

Answer:

The frequency of the second harmonic (2f_o) is 11.97 Hz.

Explanation:

Given;

mass of the string, m = 25 g = 0.025kg

tension on the string, T = 43 N

length of the string, L = 12 m

The speed of wave on the string is given as;

v = \sqrt{\frac{T}{\mu} }

where;

μ is mass per unit length = 0.025 / 12 = 0.002083 kg/m

v = \sqrt{\frac{43}{0.002083} }\\\\v  = 143.678 \ m/s

The wavelength of the first harmonic wave is given as;

L = \frac{1}{2} \lambda _o\\\\\lambda _o = 2L \\\\\lambda _o = 2 \ \times \ 12\\\\\lambda _o = 24 \ m

The frequency of the first harmonic is given as;

f_o = \frac{v}{\lambda _o} = \frac{v}{2L} = \frac{143.678}{24} = 5.99 \ Hz\\\\

The wavelength of the second harmonic wave is given as;

L = \lambda_1 \\\\\lambda_1 = 12 \ m

The frequency of the second harmonic is given as;

f_1 = \frac{v}{\lambda _1} = \frac{143.678}{12} = 11.97 \ Hz = 2(\frac{v}{\lambda _0}) = 2f_o

Therefore, the frequency of the second harmonic (2f_o) is 11.97 Hz.

8 0
3 years ago
If each of the three rotor helicopter blades is 3.50 m long and has a mass of 120 kg , calculate the moment of inertia of the th
devlian [24]

Answer:

1470kgm²

Explanation:

The formula for expressing the moment of inertial is expressed as;

I = 1/3mr²

m is the mass of the body

r is the radius

Since there are three rotor blades, the moment of inertia will be;

I = 3(1/3mr²)

I = mr²

Given

m = 120kg

r = 3.50m

Required

Moment of inertia

Substitute the given values and get I

I = 120(3.50)²

I = 120(12.25)

I = 1470kgm²

Hence the moment of inertial of the three rotor blades about the axis of rotation is 1470kgm²

7 0
3 years ago
Are the stack temperature and oxygen reasonable for these operating conditions? if not, what oxygen and stack temperature would
Anton [14]

Stack temperatures typically range from 350 to 450 degrees Fahrenheit. A 2.5% efficiency loss occurs for every 100 degrees over that temperature. The majority of buildings schedule annual boiler cleanings at regular intervals, but if you see those figures rise, it's time for a cleaning.

Excess air is required to completely burn the fuel since the air and fuel cannot combine exactly in a burner. Additionally, any leaks in the heater will draw air into the firebox that doesn't pass through the burners since the furnace or boiler firebox operates at a little negative gauge pressure. Fuels that are gaseous, like natural gas, burn more readily than fuels that are liquid or solid. Depending on the fuel type, different surplus air requirements will apply.

Learn more about temperature here-

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3 0
1 year ago
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