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Vladimir79 [104]
3 years ago
8

Difference between of echo and reverberation​

Physics
1 answer:
KiRa [710]3 years ago
5 0

Answer:

A difference between of echo and reverberation​  is described below in details.

Explanation:

Here's a piece of immediate information: An echo is an individual consideration of a soundwave off a horizon exterior. Reverberation is the consideration of sound waves generated by the superposition of the before-mentioned echoes. ... A reverberation can happen when a sound wave is displayed off a nearby covering.

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A car has 400 kgm/s worth of momentum and runs into a truck initially at rest. What is the initial momentum of the truck?
prisoha [69]

Answer:

0 kgm/s

Explanation:

The momentum is the product of mass(m) and velocity(v).

Initially the velocity of truck is 0 m/s so the product of mass and velocity becomes 0.

It does not matter what is the weight of truck, because the velocity will make the product of m*v = 0

It does not matter what is the momentum of car.

8 0
3 years ago
What is the wavelength (in nm) of a photon emitted during transition from the n = 3 state to the n = 1 state in the H atom?
Mkey [24]

Answer:

\lambda=103\ nm

Explanation:

E_n=-2.179\times 10^{-18}\times \frac{1}{n^2}\ Joules

For transitions:

Energy\ Difference,\ \Delta E= E_f-E_i =-2.179\times 10^{-18}(\frac{1}{n_f^2}-\frac{1}{n_i^2})\ J=2.179\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J

\Delta E=2.179\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J

Also, \Delta E=\frac {h\times c}{\lambda}

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

So,  

\frac {h\times c}{\lambda}=2.179\times 10^{-18}(|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)\ J

\lambda=\frac {6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times (|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)}\ m

So,  

\lambda=\frac {6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times (|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)}\ m

Given, n_i=3\ and\ n_f=1

\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times |(\frac{1}{3^2} - \dfrac{1}{1^2})}|\ m

\lambda=\frac{10^{-26}\times \:19.878}{10^{-18}\times \:2.179|\left(\frac{1}{9}-\frac{1}{1}\right)|}\ m

\lambda=1.03\times 10^{-7}\ m

1 m = 10⁻⁹ nm

\lambda=103\ nm

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