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vagabundo [1.1K]
3 years ago
11

How many grams of Br are in 345g of CaBr2?

Chemistry
1 answer:
nadya68 [22]3 years ago
4 0

Answer:

276g of Br are present

Explanation:

To solve this question we need to find the moles of CaBr2 using its molar mass -CaBr2: 199.89g/mol-. As 1 mole of CaBr2 contains 2 moles of Br we can find the moles of Br and its mass:

<em>Moles CaBr2:</em>

345g * (1mol/199.89g) = 1.7259 moles CaBr2

<em>Moles Br:</em>

1.7259 moles CaBr2 * (2mol Br / 1mol CaBr2) = 3.4519 moles Br

<em>Mass Br -Molar mass: 79.904g/mol-</em>

3.4519 moles Br * (79.904g/mol) = 276g of Br are present

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