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3 years ago

Balance the following equations:

Chemistry

1 answer:

Brilliant_brown [7]3 years ago

6 0

Answer:

1) 0 C2H4O2 + 0 O2 -> 0 CO2 + 0 H2O (balanced)

2) V2O5 + CaS -> CaO + V2S5

just additional info: V2O5 is divanadium pentaoxide

LHS (Left hand side)

V: 2

O: 5

Ca: 1

S: 1 x 5 [to balance with the right hand side of the equation]

RHS (Right hand side)

V: 2

O: 1 x 5 [to balance with the left hand side of the equation]

Ca: 1

S: 5

When you balance any elements, you have to balance the whole chemical compound.

Thus,

V2O5 + 5 CaS -> 5 CaO + V2S5

LHS CHECK:

V: 2

O: 5

Ca: 5

S: 5

RHS CHECK:

V: 2

O: 5

Ca: 5

S: 5

3) S8 + O2 -> SO2

LHS:

S: 8

O: 2

RHS:

S: 1 x 8 [to balance with LHS]

O: 2

When you balance any elements, you have to balance the whole chemical compound.

S8 + O2 -> 8 SO2

When we add 8 to the RHS, it gives us 8S, 16 O.

In order to balance that into the RHS, I need to multiply the O2 by 8, which will give 8(O2) = 16 O particles.

Therefore, S8 + 8 O2 -> 8 SO2 is the final answer for (3).

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Describe the differences between bonding in an ionic compound and bonding in a covalent molecule.

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a covalent bond and an ionic bond. An ionic bond if formed from the transfer of electrons from the outer shell of atoms. ... An example of this is NaCl, where the sodium atom becomes Na+ due to the loss of electrons, and the chlorine atom becomes the negatively charged chloride (Cl-).

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3 years ago

The solubility of magnesium phosphate at a given temperature is 0.173 g/L. Calculate the Ksp at this temperature. After you calc

jek_recluse [69]

Answer: $K_{sp}=1.25\times 10^{-14}$

$pK_{sp}=13.90$

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as $K_{sp}$

The equation for the ionization of magnesium phosphate is given as:

$Mg_3(PO_4)_2\rightarrow 3Mg^{2+}+2PO_4^{3-}$

When the solubility of $Mg_3(PO_4)_2$ is S moles/liter, then the solubility of $Mg^{2+}$ will be 3S moles\liter and solubility of $PO_4^{3-}$ will be 2S moles/liter.

Thus S = 0.173 g/L or $\frac{0.173g/L}{262.8g/mol}=0.00065mol/L$

$K_{sp}=(3S)^3\times (2S)^2$

$K_{sp}=108S^5$

$K_{sp}=108\times (0.00065)^5=1.25\times 10^{-14}$

$pK_{sp}=-log(K_{sp})=\log (1.25\times 10^{-14})=13.90$

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3 years ago

Salt is dissolved in a flask of tap water. Distilling the mixture causes the salt to separate from the water. Which type of ener

Alik [6]

Heat energy is required.
In distillation, the solution is first heated, where heat energy is required, such as using a bunsen burner.
When the solution is heated, the water may reach its boiling point and evaporate. However, salt does not. When water molecules evaporates, it travels through a condenser that cools it down into liquid again. Therefore we get pure water. Salt is also obtained in the original beaker.
Therefore to first start this process, heat energy is required.

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3 years ago

Read 2 more answers

The atomic number of gold (Au) is 79, and it has a mass number of 197. How many electrons are present in each atom of gold?

aliya0001 [1]

There would be 79 electrons present in each atom of gold. I hope this helps :)

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3 years ago

Consider this reaction: NH4 HPO42− → NH3 H2PO4− Which is the Bronsted-Lowry acid ? NH4 HPO42- HPO42– H2PO4–.

kvv77 [185]

Bronsted - Lowry acid in the given reaction is NH₄, as it gives H⁺ ion.

<h3>What is Bronsted - Lowry acid?</h3>

According to the theory of Bronsted - Lowry, acids are those substances which gives H⁺ ion or proton in the aqueous medium.

Given chemical reaction is :

NH₄ + HPO₄²⁻ → NH₃ + H₂PO₄⁻

In the above reaction NH₄ is the Bronsted - Lowry acid as it gives H⁺ ion in the reaction and changes to NH₃ which is the conjugate base of NH₄. Whereas HPO₄²⁻ is the Bronsted - Lowry base as it accepts the H⁺ ion to form H₂PO₄⁻ which is the conjugate acid of it.

Hence, option (1) is correct, i.e. NH₄ is the Bronsted - Lowry acid.

To know more about Bronsted - Lowry acid, visit the below link:

brainly.com/question/1435076

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3 years ago