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4 years ago

What is the universal force of attractions between bodies

1 answer:

8 0

In physics, the force of attraction between two objects is gravitational force.<span>Isaac Newton's law of universal gravitation defines the concept of gravitational force, stating that a gravitational attraction exists between all objects.

Hope this helps!! :D</span>

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What factor, according to the data in the table above, has the greatest impact on species loss?

Finger [1]

B. The area of the island is your answer :)

6 0

2 years ago

Given the reaction: S + O2 ---> SO2

saul85 [17]

Answer: 67.1 moles of SO2

Explanation:

Since the equation is already balanced, you would just need to cancel out the O2 and multiple the 67.1 mol by the 1 mol of SO2 to get your answer.

3 0

4 years ago

At one point in your life, you might have played on a swing. Have you ever wondered why, after the first swing, it will slow dow

cestrela7 [59]

Answer:

at the top of the swing

at the bottom of the swing

Explanation:

7 0

3 years ago

What mass of water in grams will fill a tank 126cm long, 47 cm wide, and 13 cm high

Shtirlitz [24]

Answer:

Mass = 76986 g

Explanation:

Given data:

Dimensions of tank = 126 cm× 47 cm× 13 cm

Mass of water required to filled = ?

Solution:

First of all we will calculate the volume of tank which is equal to the volume of water required to fill it.

Volume = length ×height ×width

Volume = 126 cm × 13 cm× 47 cm

Volume = 76986 cm³

Mass of water:

Mass = density × volume

density of water is 1 g/cm³

Mass = 1 g/cm³× 76986 cm³

Mass = 76986 g

8 0

3 years ago

An analytical chemist is titrating of a solution of ethylamine with a solution of . The of ethylamine is . Calculate the pH of t

Elenna [48]

Answer:

pH=11.

Explanation:

Hello!

In this case, since the data is not given, it is possible to use a similar problem like:

"An analytical chemist is titrating 185.0 mL of a 0.7500 M solution of ethylamine(C2HNH2) with a 0.4800 M solution of HNO3.ThepK,of ethylamine is 3.19. Calculate the pH of the base solution after the chemist has added 114.4 mL of the HNO3 solution to it"

Thus, for the reaction:

$C_2H_5NH_2+H^+\rightleftharpoons C_2H_5NH_4^+$

Tt is possible to compute the remaining moles of ethylamine via the following subtraction:

$n_{ethylamine}=0.1850L*0.7500mol/L=0.1365mol\\\\n_{acid}=0.1144L*0.4800mol/L=0.0549mol\\\\n_{ethylamine}^{remaining}=0.1365mol-0.0549mol=0.0816mol$

Thus, the concentration of ethylamine in solution is:

$[ethylamine]=\frac{0.0816mol}{0.1850L+0.1144L}=0.2725M$

Now, we can also infer that some salt is formed, and has the following concentration:

$[salt]=\frac{0.0549mol}{0.1850L+0.1144L}=0.1834M$

Therefore, we can use the Henderson-Hasselbach equation to compute the resulting pOH first:

$pOH=pKb+log(\frac{[salt]}{[base]} )\\\\pOH=3.19+log(\frac{0.1834M}{0.2725M})\\\\pOH=3.0$

Finally, the pH turns out to be:

$pH=14-pOH=14-3\\\\pH=11$

NOTE: keep in mind that if you have different values, you can just change them and follow the very same process here.

Best regards!

4 0

3 years ago