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4 years ago

Create one expression to solve question #3. Need help with #4. (Question with diagram)

Mathematics

1 answer:

tamaranim1 [39]4 years ago

4 0

Let h to be the height, b base of the triangle, l length, w width:

Area = bh + lw

h=l

Area = 3(8)+3(8)

Area= 48 in²

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three times the lesser of two consecutive even integers is 6 less than six times the greatest number. find the integers.

kakasveta [241]

3x-6=6(x+2) 3x-6=6x+12 3x-6x=6+12 -3x=18 X= 18/-3 X= -6 first number . For second number you substitute x+2. -6+2=-4

3 0

3 years ago

26.72 ÷ 4.7 (Round to the nearest hundredth)

padilas [110]

Answer:

6 0r 5.6 rounded to the nearest hundredth

Step-by-step explanation:

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3 years ago

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She determined that the solution is (–3, –3). Is she correct? If not, explain why. Yes, she is correct. No. She switched the x a

LenaWriter [7]

Answer: No she used the wrong slopes when graphing the equations

Step-by-step explanation:

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3 years ago

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In a class of 100 students, 25 have hardcover and 75 students have paperback textbooks. If you randomly choose 15 students in th

Gnom [1K]

Answer:

23.72% probability that 3 of them have hardcover texts.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the students are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

If you randomly choose 15 students in this class, find the probability that 3 of them have hardcover texts.

Desired outcomes:

3 with hardcover texts, from a set of 25.

15-3 = 12 with paperback texts, from a set of 75. So

$D = C_{25,3}*C_{75,12} = \frac{25!}{3!(22)!}*\frac{75!}{12!(63)!} = 6 \times 10^{16}$

Total outcomes:

15 students from a set of 100. So

$T = C_{100,15} = \frac{100!}{15!85!} = 2.53 \times 10^{17}$

Probability:

$P = \frac{D}{T} = \frac{6 \times 10^{16}}{2.53 \times 10^{17}} = 0.2372$

23.72% probability that 3 of them have hardcover texts.

7 0

3 years ago

Evaluate the determinant for the following matrix: A. –42 B. –36 C. 12 D. 10

Gemiola [76]

Missing information, you didn't provide the matrix

6 0

4 years ago