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Paladinen [302]
3 years ago
8

If f(x) = 3x^2 - 4 and g(x) = x+2, find (f - g)(x).

Mathematics
2 answers:
galina1969 [7]3 years ago
8 0

Answer:

3x^2-x-6

Step-by-step explanation:

f(x) = 3x^2 - 4

g(x) = x+2

(f - g)(x)= 3x^2 - 4-( x+2)

Distribute the minus sign

(f - g)(x)= 3x^2 - 4- x-2

Combine like terms

            = 3x^2-x-6

sergey [27]3 years ago
5 0

Answer:

(f - g)(x) = 3 x² - x - 6

Step-by-step explanation:

<u>Given</u> :-

  • f(x) = 3x² - 4
  • g(x) = x+2

<u>Find :-</u>

  • (f - g)(x).

<u>Solution :-</u>

(f - g)(x) = 3 x² - 4 - ( x + 2 )

Distribute the ( - ) minus sign

(f - g)(x) = 3 x ² - 4 - x - 2

Combine like terms

(f - g)(x) = 3 x ² - x - 4 - 2

(f - g)(x) = 3 x² - x - 6

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Determine whether the series is arithmetic or geometric. Then evaluate the finite series for the specified number of terms. 10 +
Salsk061 [2.6K]

Answer:

10 + 7 + 4 + . . .; n = 5​

The series is arithmetic

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Or:

10 + (-3) = 7

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--------------------------------------------------------------------------

<u>Another example</u>:

Arithmetic:

5, 9, 13, 17

common difference = 4

5 + 4 = 9

9 + 4 = 13

Geometric:

4, 8, 16, 32

4 × 2 = 8

8 × 2 = 16

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--------------------------------------------------------------------------

10 + 7 + 4 + . . .; n = 5​

a₁ = 10

a₂ = 7

a₄ = a₃ + d = 4 + (-3) = 4 - 3 = 1     (d = common difference)

a₅ = a₄ - 3 = 1 - 3 = -2

Or with formula:

d=a_{n} -a_{n-1}

d = a₂ - a₁ = 7 - 10 = -3

aₙ = a₁ + (n - 1)d

fourth term = a₄ = 10 + (4 - 1)(-3) = 10 + 3(-3) = 10 + (-9) = 10 - 9 = 1

fifth term = a₅ = 10 + (5 - 1)(-3) = 10 + 4(-3) = 10 + (-12) = 10 - 12 = -2

Sum of the finite series (if n = 5):

S_{n} =\frac{n(a_{1} +a_{n} )}{2} \\S_{5} =\frac{5(a_{1} +a_{5} )}{2} \\S_{5} =\frac{5(10 +(-2) )}{2} \\S_{5} =\frac{5(8 )}{2} =\frac{40}{2} =20

Manual count: S₅ = 10 + 7 + 4 + 1 + (-2) = 20

7 0
2 years ago
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