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3 years ago

What do you do if your Bf call you selfish -_-

Chemistry

2 answers:

VLD [36.1K]3 years ago

7 0

Answer:

depends on what he called u selfish for

....

ryzh [129]3 years ago

4 0

Answer:

cry?!

Explanation:

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(Numerical problems) A car is running with the velocity of 72km/h. What will be it's velocity after 5s if it's acceleration is -

kodGreya [7K]

The car's velocity after 5s : 10 m/s

<h3>Further explanation</h3>

Given

velocity=v=72 km/h=20 m/s

time=t = 5 s

acceleration=a = -2 m/s²

Required

velocity after 5s

Solution

Straight motion changes with constant acceleration

$\tt v_f=v_i+at$

vf=final velocity

vi = initial velocity

Input the value :

$\tt v_f=20+(-2).5\\\\v_f=20-10\\\\v_f=10~m/s$

The car is decelerating (acceleration is negative) so that its speed decreases

4 0

3 years ago

Can anyone please help me with my chemistry homework? It’s about molarity. I can’t message anyone here because I’m new to brainl

GREYUIT [131]

Answer:

ok sure

Explanation:

4 0

2 years ago

To a 25.00 mL volumetric flask, a lab technician adds a 0.150 g sample of a weak monoprotic acid, HA , and dilutes to the mark w

Elis [28]

<u>Answer:</u> The number of moles of weak acid is $4.24\times 10^{-3}$ moles.

<u>Explanation:</u>

To calculate the moles of KOH, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}\text{Volume of solution (in L)}}$

We are given:

Volume of solution = 43.81 mL = 0.04381 L (Conversion factor: 1L = 1000 mL)

Molarity of the solution = 0.0969 moles/ L

Putting values in above equation, we get:

$0.0969mol/L=\frac{\text{Moles of KOH}}{0.04381}\\\\\text{Moles of KOH}=4.24\times 10^{-3}mol$

The chemical reaction of weak monoprotic acid and KOH follows the equation:

$HA+KOH\rightarrow KA+H_2O$

By Stoichiometry of the reaction:

1 mole of KOH reacts with 1 mole of weak monoprotic acid.

So, $4.24\times 10^{-3}mol$ of KOH will react with = $\frac{1}{1}\times 4.24\times 10^{-3}=4.24\times 10^{-3}mol$ of weak monoprotic acid.

Hence, the number of moles of weak acid is $4.24\times 10^{-3}$ moles.

6 0

3 years ago

What is the value for ∆Soreaction for the following reaction, given the standard entropy values? 2H2S(g) + SO2(g) 3Srhombic(s) +

Mademuasel [1]

Answer: $\Delta S^{0}$ for the reaction is -186.75 J/K

Explanation:

Change in entropy ( $\Delta S^{0}$ ) for the given reaction under standard condition is given by-

$\Delta S^{0}$ = $[3\times S_{rhombic}^{0}_{(s)}]+[2\times S_{H_{2}O}^{0}_{(g)}]-[2\times S_{H_{2}S}^{0}_{(g)}]-[1\times S_{SO_{2}}^{0}_{(g)}]$

So $\Delta S^{0}$ = $[3\times 31.8 J/K.mol]+[2\times 188.825 J/K.mol]-[2\times 205.79 J/K.mol]-[1\times 248.22 J/K.mol]$ = -186.75 J/K

5 0

2 years ago

T/F

kifflom [539]

True. Nuclear fusion of hydrogen to form helium occurs naturallyin the sun and other stars. It takes place only at extremely high temperatures.

8 0

3 years ago