Answer: I believe it’s the last one I am so sorry if I’m wrong you sound urgent and I wanted to help so I read up on wiki
Explanation:
All of the atoms of a saturated hydrocarbon are bonded by 4 pairs of electrons in case of a carbon and 1 pair in case of hydrogen.
Saturated hydrocarbons are hydrocarbons with only single bonds. Each carbon has a maximum number of hydrogen atoms bonded to it. A good example is alkanes. On the other hand the unsaturated hyrocarbon are hydrocarbons with at least one double bond or triple bond.
Answer:
The correct answer is: 6.6 g MgO
Explanation:
First we have to write and balance the chemical reaction as follows:
2Mg(s) + O₂(g) → 2MgO(s)
That means that 2 moles of Mg(s) react with 1 mol of O₂(g) to give 2 moles of MgO(s). If Mg is totally consumed and a mass of O₂ remains unaltered after reaction, t<em>he limiting reactant is Mg</em>. We use the limiting reactant to calculate the mass of product.
According to the balanced chemical equation, 2 moles of Mg(s) produce 2 moles of MgO(s).
2 moles Mg = 2 mol x molar mas Mg= 2 mol x 24.3 g/mol = 48.6 g Mg
2 moles MgO= 2 mol x (molar mass Mg + molar mass O) = 2 mol x (24.3 g/mol + 16 g/mol) = 80.6 g MgO
The stoichiometric ratio is 80.6 g MgO/48.6 g Mg. So, we multiply this ratio by the mass of consumed Mg (4.0 g) in order to obtain the produced mass of MgO:
4.0 g Mg x 80.6 g MgO/48.6 g Mg = 6.63 g MgO
6.6 grams of magnesium oxide are formed.
Answer:
Mass of KOH = 497.78 g
Explanation:
Given data
mass of KOH = ?
number of KOH molecules = 5.34 × 10²⁴
molar mass of KOH = 56.12 g/mol
Solution
1st we find out the number of moles of KOH
<em>number of moles = number of molecules given / Avogadro number
</em>
number of moles of KOH = 5.34 × 10²⁴ / 6.022 × 10²³
number of moles of KOH = 8.87 mol
Now we find out the mass of KOH
<em>Mass of KOH = moles × molar mass</em>
Mass of KOH = 8.87 mol × 56.12 g/mol
Mass of KOH = 497.78 g
Answer:
Explanation:
Mole = no. Molecules/6.02×10^23
Mole = (8.12×10^23)/(6.02×10^23)
Mole = 1.35mole
Molar mass of CO2 = 12+ 2(16)
Molar mass= 12 + 32= 44g/mol
Mole = mass/molar mass
Mass = Mole × molar mass
Mass = 1.35× 44
Mass= 59.35g
