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kap26 [50]
3 years ago
14

Anyone can help? This will be really appreciated! 35 POINTS!!

Chemistry
2 answers:
Vlad1618 [11]3 years ago
8 0

Answer: 5. You can go 343.2 miles 6. 840960 minutes in a 1.6 years

Hope that helps :)

lara [203]3 years ago
7 0

Answer: 5. You can go 343.2 miles 6. 840960 minutes in a 1.6 years Maybe that works

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What is the meaning of a chemical reaction?
Margarita [4]
When you have a chemical reaction, it means something goes wrong with your chemicals.
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4 years ago
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Which form of energy is converted to thermal energy when propane burns in air?
kolezko [41]
Chemical because the propane has stored chemical energy which is being released and a by-product of that propane is heat or themal energy.
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3 years ago
What is the molarity of a solution that contains 14 moles of solute and 2 liters of solution?
Nata [24]

Answer:

  7 M

Explanation:

The molarity is defined as "moles per liter." Here, it is ...

  (14 moles)/(2 liters) = 7 moles/liter = 7 M

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3 years ago
Helppp pleaseeee......
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mL

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milliliters

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3 years ago
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Mixtures of benzene and cyclohexane exhibit ideal behavior. A solution was created containing 1.5 moles of liquid benzene and 2.
goblinko [34]

Answer:

Vapour pressure of cyclohexane at 50°C is 490torr

Vapour pressure of benzene at 50°C is 90torr

Explanation:

Using Raoult's law, pressure of a solution is defined by the sum of the product sbetween mole fraction of both solvents and pressure of pure solvents.

P_{solution} = X_{A}P^0_{A}+X_{B}P^0_{B}

In the first solution:

X_{cyclohexane}=\frac{2.5mol}{2.5mol+1.5mol} =0.625

X_{benzene}=\frac{1.5mol}{2.5mol+1.5mol} =0.375

340torr = 0.625P^0_{A}+0.375P^0_{B} <em>(1)</em>

For the second equation:

X_{cyclohexane}=\frac{3.5mol}{3.5mol+1.5mol} =0.700

X_{benzene}=\frac{1.5mol}{3.5mol+1.5mol} =0.300

370torr = 0.700P^0_{A}+0.300P^0_{B}<em>(2)</em>

Replacing (2) in (1):

340torr = 0.625P^0_{A}+0.375(1233.3-2.333P^0_{A})

340torr = 0.625P^0_{A}+462.5-0.875P^0_{A}

-122.5torr = -0.250P°A

P^0_{A} = 490 torr

<em>Vapour pressure of cyclohexane at 50°C is 490torr</em>

And for benzene:

370torr = 0.700*490torr+0.300P^0_{B}

P^0_{B}=90torr

<em>Vapour pressure of benzene at 50°C is 90torr</em>

3 0
3 years ago
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