Answer:
T = 5325 s
Explanation:
Given:
- Specific angular momentum h = 48,000 km^2 /s
- Radius of earth r_e = 6.3781 *10^3 km
Find:
The period of orbit
The relationship between Specific angular momentum h and period of orbit is as follows:
h = 2*pi*r_e^2 / T
T = 2*pi*r_e^2 / h
Hence, Plug the values
T = 2*pi*(6.3781 *10^3)^2 / 48,000
T = 5325 s = 1.48 h
Answer:
The maximum height reached by the ball is 20.4 m.
Explanation:
We have,
Mass of a ball is 15 kg
It is thrown straight upward with a speed of 20 m/s.
It is required to find the maximum height reached by the ball. Let the maximum height is h. As energy is conserved, the potential energy at the ball's highest point is equal to the kinetic energy when it is thrown. So,
So, the maximum height reached by the ball is 20.4 m.
Answer:
The kinetic energy of the clam at a height of 5.0 m is 5.19 J and the speed of the clam at that height is 9.71 m/s.
<u>Explanation:
</u>
<em>Mechanical energy is constant throughout the travel</em>, we know that <em>mechanical energy is calculated by adding potential energy and kinetic energy</em>. Potential energy = ,
Kinetic energy = and Mechanical energy = Kinetic energy is zero at initial point. Now mechanical energy of clam with m=0.11kg,g=9.81,h=9.8 m is = 0.11×9.81×9.8 = 10.58 J.
Mechanical energy of clam at a height of 5.0 m = =. We know that mechanical energy is constant hence, <em>mechanical energy of clam at height 9.8 m is equal to mechanical energy at height 5.0 m</em>. This is represented as following
10.58 = 10.58 – 5.39 = 5.19 = kinetic energy of the clam is 5.19 J.
Now speed of the clam at height 5.0 m is 5.19 = 94.36 = = 9.71 m/s. The speed of the clam is 9.71 m/s.
Answer:
Explanation:
Begin by remembering that at the stone's max height, the final velocity there is 0. Being in possession of that information along with the fact that the pull of gravity due to acceleration is -9.8 m/s/s, we can use the equation
Δx where v is the final velocity, v₀ is the initial velocity, a is the pull of gravity, and Δx is the displacement. Filling in:
0 = v₀² - 98 so
98 = v₀² and
v = 9.9 m/s Now we can put that into the KE equation.
and
so
m = .20 kg
Answer: 0.5
Explanation:
The modulus of elasticity (called <em>"alargamiento unitario"</em> in spanish) of a spring is given by the following formula:
Where:
is the original length of the spring
is the elongation of the spring, being the length of the spring after a force is applied to it.
Then: