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slega [8]
3 years ago
7

If you heat a fixed quantity of gas, which of the following statements are true?Check all that apply.a.The volume will always in

crease.b.If the pressure is held constant, the volume will increase.c.The product of volume and pressure will increase.d.The density of the gas will increase.e.The quantity of gas will increase.
Physics
1 answer:
kherson [118]3 years ago
8 0

Answer:

Explanation:

Given

there is fix Quantity of gas i.e. mass of gas is constant

From ideal gas Equation

PV=nRT

(a) volume always increases is not true as Pressure can also be increased .

(b)If Pressure is constant along with mass then as Temperature increases, Volume also increases.

(c)true , Product of Pressure and volume depends upon temperature thus it also increases with temperature.

(d)Density of gas may or may not increases

As density is \frac{mass}{volume}

volume may increase or decrease as temperature increase .

(e)false

as it clearly stated that quantity of fixed therefore there is no change in gas

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A 98-kg fullback, running at 5.0 m/s, attempts to dive directly across the goal line for a touchdown. Just as he reaches the lin
Troyanec [42]

Answer:

(a) Explained below

(b) v_f=0.35\ m/s

(c) Yes

Explanation:

<u>Law Of Conservation Of Linear Momentum</u>

The total linear momentum of a system of particles or objects is conserved unless an external force is acting on the system. The formula for the momentum of a body with mass m and velocity v is P=mv. If there is a system of bodies, then the total linear momentum is the sum of the individual momentums

P=m_1v_1+m_2v_2+...+m_nv_n

When objects collide and join together, the only final mass is the sum of all masses, all traveling at the same speed.

Our m_1=98\ kg fullback runs at v_1=5\ m/s. Two two 68-kg linebackers attempt to stop him, one at -2.0 m/s and the other at -4.0 m/s. The negative value is because the run against the positive direction, taken in the direction of the fullback.

(a) Before the event, there is a total linear momentum, computed as the sum of the momentums of each player as shown

p_1=m_1v_1=(98)(5)=490 Kg\ m/s

p_2=m_2v_2=(68)(-4)=-272 kg\ m/s

p_3=m_3v_3=(68)(-2)=-136 kg\ m/s

p_t=p_1+p_2+p_3=390-272-136=82\ kg\ m/s

After the collision, all the players keep joined in one single mass of.

m_t=98+68+68=234\ kg

They will move at a speed which will be computed below

(b) The final momentum of the system is

p_f=m_tv_f=82\ kg\ m/s

Since the linear momentum is conserved, the final speed v_f is common to all of the players. Let's solve to find it

\displaystyle v_f=\frac{p_f}{m_t}

\displaystyle v_f=\frac{82}{234}

v_f=0.35\ m/s

(c) Since the final speed of the players is positive, it means the touchdown was actually scored, the fullback moved forward across the goal line, the positive reference.

5 0
3 years ago
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Alex787 [66]
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4 0
3 years ago
Two neutral metal spheres on wood stands are touching. A negatively charged rod is held directly above the top of the left spher
Paha777 [63]

Answer:

The right sphere is negatively charged, the left sphere is charged positively.

Explanation:

When a negatively charged rod is held above the top of left sphere, the rod will attract positive charges and repel negative charges. As the sphere are initially touching each other so positive charges from the both spheres will moves toward the rod. When we separate the spheres positive charges from right sphere have already moved toward the rod i.e. left sphere, creating a deficiency of positive charges in the right sphere and excessiveness of positive charges in left sphere , hence the right sphere will remain negatively charged and left sphere will remain positively charged.

4 0
3 years ago
Which statement is the best example of pseudoscience?
Nady [450]
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5 0
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The truck in which
sertanlavr [38]

Answer:

m = 4

Explanation:

We have,

You apply a force of  600 N to the branch  which acts as a lever. It means it is input force, IF = 600 N

The rear of the truck  weighs 2,400 N. It means it is output force, OF = 2400 N

The ratio of output force to the input force is equal to the mechanical advantage of the lever arm. It is given by :

m=\dfrac{2400}{600}\\\\m=4

So, the mechanical  gain of the lever arm is 4.

8 0
3 years ago
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