Answer:
Echolocation
Explanation:
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Answer:
The time rate of change of flux is
![\frac{V}{s}](https://tex.z-dn.net/?f=%5Cfrac%7BV%7D%7Bs%7D)
Explanation:
Given :
Current
A
Area of plate
![m^{2}](https://tex.z-dn.net/?f=m%5E%7B2%7D)
Plate separation
m
(A)
First find the capacitance of capacitor,
![C = \frac{\epsilon _{o} A }{d}](https://tex.z-dn.net/?f=C%20%3D%20%5Cfrac%7B%5Cepsilon%20_%7Bo%7D%20A%20%7D%7Bd%7D)
Where ![\epsilon _{o} = 8.85 \times 10^{-12}](https://tex.z-dn.net/?f=%5Cepsilon%20_%7Bo%7D%20%3D%208.85%20%5Ctimes%2010%5E%7B-12%7D)
![C = \frac{8.85 \times 10^{-12 } \times 36 \times 10^{-4} }{4 \times 10^{-3} }](https://tex.z-dn.net/?f=C%20%3D%20%5Cfrac%7B8.85%20%5Ctimes%2010%5E%7B-12%20%7D%20%5Ctimes%2036%20%5Ctimes%2010%5E%7B-4%7D%20%20%7D%7B4%20%5Ctimes%2010%5E%7B-3%7D%20%7D)
F
But ![C = \frac{Q}{V}](https://tex.z-dn.net/?f=C%20%3D%20%5Cfrac%7BQ%7D%7BV%7D)
Where ![Q = It](https://tex.z-dn.net/?f=Q%20%3D%20It)
![C = \frac{It}{V}](https://tex.z-dn.net/?f=C%20%3D%20%5Cfrac%7BIt%7D%7BV%7D)
![V = \frac{It}{C}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7BIt%7D%7BC%7D)
Now differentiate above equation wrt. time,
![\frac{dV}{dt} = \frac{I}{C}](https://tex.z-dn.net/?f=%5Cfrac%7BdV%7D%7Bdt%7D%20%3D%20%5Cfrac%7BI%7D%7BC%7D)
![= \frac{0.106}{7.9 \times 10^{-12} }](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B0.106%7D%7B7.9%20%5Ctimes%2010%5E%7B-12%7D%20%7D)
![\frac{V}{s}](https://tex.z-dn.net/?f=%5Cfrac%7BV%7D%7Bs%7D)
Therefore, the time rate of change of flux is
![\frac{V}{s}](https://tex.z-dn.net/?f=%5Cfrac%7BV%7D%7Bs%7D)
Answer:
An electromagnet is the device through which runs current and it creates a magnetic field.
Answer:
Power, P = 307.31 W
Explanation:
It is given that,
Kasek climb at an angle of 6° with the horizontal at a steady speed of 4.0 m/s.
The total mass of bicycle and Kasek is 75 kg
We need to find the Kasek's power output to climb the same hill at the same speed. The angle is made with the horizontal. It means that,
F = F sinθ
So,
Power output is given by :
![P=mg\sin\theta\times v\\\\P=75\times 9.8\times \sin(6)\times 4\\\\P=307.31\ W](https://tex.z-dn.net/?f=P%3Dmg%5Csin%5Ctheta%5Ctimes%20v%5C%5C%5C%5CP%3D75%5Ctimes%209.8%5Ctimes%20%5Csin%286%29%5Ctimes%204%5C%5C%5C%5CP%3D307.31%5C%20W)
So, Kasek's power output to climb the same hill is 307.31 W.