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VladimirAG [237]
2 years ago
10

The decomposition of mercury (ii) oxide at high temperature, is it an endothermic or exothermic process? Write a chemical reacti

on for this process.

Chemistry
2 answers:
gulaghasi [49]2 years ago
6 0

Answer:

that will be endothermic reaction...... as oxides of mercury decomposes and break s into simpler elements by absorbing energy

Explanation:

hope it helped u buddy

algol132 years ago
3 0

Answer: endothermic, 2HgO\rightarrow 2Hg+O_2

Explanation:

Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

All decomposition reactions are endothermic as heat is absorbed by the reactants to break the bonds in the reactants.

Decomposition of HgO is given by:

2HgO\rightarrow 2Hg+O_2

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Misha Larkins [42]

Answer:

<h3>A-5N B-6N C-7N D-8N</h3>

Explanation:

i hope it helps ;)

5 0
3 years ago
The weather report says that if the temperature drops 10°, it will reach 25° below zero. The current temperature T can be found
Neporo4naja [7]

Answer:

The current temperature is -15° (15° below zero)

Explanation:

The temperature drops 10°:

T-10°

It will reach 25° below zero:

T - 10° = -25°

We add 10° in both members of the equation:

T - 10° +10° = -25° +10°

The equation is simplified as follows:

T = -25° +10°

T = -15°

The integer -15° can be expressed as 15° below zero.

8 0
2 years ago
*
Murrr4er [49]

The answer fam is......... False

7 0
3 years ago
The reaction shown below occurs in the blood between hemoglobin (Hb) and oxygen.
OlgaM077 [116]

Answer:

A, B, C

Explanation:

Notice that this reaction involves double arrows, meaning this represents an equilibrium reaction in which we observe a forward reaction (combination of hemoglobin and oxygen) and a reverse reaction (decomposition of the oxyhemoglobin complex).

Upon inhalation of oxygen, it accesses the blood of a person and binds to hemoglobin, so the following reaction proceeds to the right.

Similarly, the opposite process takes place in muscles, oxyhemoglobin is decomposed back into hemoglobin and oxygen.

The equilibrium constant reaction is relatively high, since at standard conditions, this is a spontaneous reaction, hemoglobin combines with oxygen without any additional external source of energy.

7 0
3 years ago
Calculate the hydronium ion concentration in an aqueous solution with a poh of 4.33 at 25°c.
Jlenok [28]

Taking into account the definition of pH and pOH, the hydronium ion concentration in an aqueous solution with a pOH of 4.33 at 25°c is 2.138×10⁻¹⁰ M.

<h3>Definition of pH</h3>

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or  hydronium ion H₃O⁺:

pH= - log [H⁺]= - log [H₃O⁺]

<h3>Definition of pOH</h3>

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

<h3>Relationship between pH and pOH</h3>

The following relationship can be established between pH and pOH:

pOH + pH= 14

<h3>Concentration of hydronium ions</h3>

Being pOH= 4.33, pH is calculated as:

pH + 4.33= 14

pH= 14 - 4.33

<u><em>pH= 9.67</em></u>

Replacing in the definition of pH the concentration of hydronium ions is obtained:

- log [H₃O⁺]= 9.67

Solving:

[H₃O⁺]= 10⁻⁹ ⁶⁷

<u><em>[H₃O⁺]= 2.138×10⁻¹⁰ M</em></u>

Finally, the hydronium ion concentration in an aqueous solution with a pOH of 4.33 at 25°c is 2.138×10⁻¹⁰ M.

Learn more about pH and pOH:

brainly.com/question/16032912

brainly.com/question/13557815

#SPJ1

4 0
2 years ago
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