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VladimirAG [237]
3 years ago
10

The decomposition of mercury (ii) oxide at high temperature, is it an endothermic or exothermic process? Write a chemical reacti

on for this process.

Chemistry
2 answers:
gulaghasi [49]3 years ago
6 0

Answer:

that will be endothermic reaction...... as oxides of mercury decomposes and break s into simpler elements by absorbing energy

Explanation:

hope it helped u buddy

algol133 years ago
3 0

Answer: endothermic, 2HgO\rightarrow 2Hg+O_2

Explanation:

Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

All decomposition reactions are endothermic as heat is absorbed by the reactants to break the bonds in the reactants.

Decomposition of HgO is given by:

2HgO\rightarrow 2Hg+O_2

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⦁ Find the concentration of H+, OH-, PH and POH of 0.03 M of magnesium hydroxide which ionizes to the extent of only 1 /3 in aqu
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Answer:

pH=12.3\\\\pOH=1.7\\

[H^+]=5x10^{-13}M

[OH^-]=0.02M

Explanation:

Hello there!

In this case, according to the given ionization of magnesium hydroxide, it is possible for us to set up the following reaction:

Mg(OH)_2(s)\rightleftharpoons Mg^{2+}(aq)+2OH^-(aq)

Thus, since the ionization occurs at an extent of 1/3, we can set  up the following relationship:

\frac{1}{3} =\frac{x}{[Mg(OH)_2]}

Thus, x for this problem is:

x=\frac{[Mg(OH)_2]}{3}=\frac{0.03M}{3}\\\\x=  0.01M

Now, according to an ICE table, we have that:

[OH^-]=2x=2*0.01M=0.02M

Therefore, we can calculate the H^+, pH and pOH now:

[H^+]=\frac{1x10^{-14}}{0.02}=5x10^{-13}M

pH=-log(5x10^{-13})=12.3\\\\pOH=14-pH=14-12.3=1.7

Best regards!

4 0
3 years ago
2-bromo-3,4-dimethylpentane is combined with t-butoxide. The product of this reaction is.
Andrej [43]

2-bromo-3,4-dimethylpentane is combined with t-butoxide. The product of this reaction is 3,4 dimethyl - 1- pentene.  

The reaction of 2-bromo-3,4-dimethylpentane is combined with t-butoxide forms 2 alkene in the elimination reaction due to steric hindrance.  The least stable alkene 3,4 dimethyl - 1- pentene is easy to make. the  t-butoxide is (CH₃)₃CO⁻. The reaction involves in this reaction is E2 elimination reaction. This reaction involves the one step reaction. The product will also form that is 3,4 dimethyl - 2 - pentene.  so the reaction involve Elimination reaction and the product due to steric hindrance is 3,4 dimethyl - 1- pentene

Thus, 2-bromo-3,4-dimethylpentane is combined with t-butoxide. The product of this reaction is 3,4 dimethyl - 1- pentene.  

To learn more about  t-butoxide here

brainly.com/question/12303978

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1 year ago
Compare the properties of protons neutrons and electrons
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Protons are positively charged. Neutrons have no charge. Electrons have a negative charge. Protons and neutrons are in the nucleus. Electrons revolve around the nucleus. 
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