Answer:
Hydrogen and Cobalt
Explanation:
Break up each individual element
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Answer:
a) H2SO4 + 2KOH -> 2H2O + K2SO4
b) 9.809 ml
Explanation:
Number of Moles = Mass/ Molar Mass
Therefore: Mass = Number of moles * Molar Mass
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Molar mass of H2SO4:
H2= 2.02
S= 32.07
O4= 64
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H2SO4 has the molar mass of 98.09
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the Moles of H2SO4 is given to be 0.100M
Therefore:
Mass= 98.09*0.1
= 9.809g
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Assuming that 1 g= 1 ml, the volume of sulfuric acid is 9.809 ml.
Answer:
pH = 1.32
Explanation:
H₂M + KOH ------------------------ HM⁻ + H₂O + K⁺
This problem involves a weak diprotic acid which we can solve by realizing they amount to buffer solutions. In the first deprotonation if all the acid is not consumed we will have an equilibrium of a wak acid and its weak conjugate base. Lets see:
So first calculate the moles reacted and produced:
n H₂M = 0.864 g/mol x 1 mol/ 116.072 g = 0.074 mol H₂M
54 mL x 1L / 1000 mL x 0. 0.276 moles/L = 0.015 mol KOH
it is clear that the maleic acid will not be completely consumed, hence treat it as an equilibrium problem of a buffer solution.
moles H₂M left = 0.074 - 0.015 = 0.059
moles HM⁻ produced = 0.015
Using the Henderson - Hasselbach equation to solve for pH:
ph = pKₐ + log ( HM⁻/ HA) = 1.92 + log ( 0.015 / 0.059) = 1.325
Notes: In the HH equation we used the moles of the species since the volume is the same and they will cancel out in the quotient.
For polyprotic acids the second or third deprotonation contribution to the pH when there is still unreacted acid ( Maleic in this case) unreacted.
Answer:
high ph -basic,low pH -acidic
Explanation:
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Answer:
their are a it is in the chemicle
Explanation:18 carbon and 4 hydrogen
so it is a toatle of 22 atoms