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VladimirAG [237]
3 years ago
10

The decomposition of mercury (ii) oxide at high temperature, is it an endothermic or exothermic process? Write a chemical reacti

on for this process.

Chemistry
2 answers:
gulaghasi [49]3 years ago
6 0

Answer:

that will be endothermic reaction...... as oxides of mercury decomposes and break s into simpler elements by absorbing energy

Explanation:

hope it helped u buddy

algol133 years ago
3 0

Answer: endothermic, 2HgO\rightarrow 2Hg+O_2

Explanation:

Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

All decomposition reactions are endothermic as heat is absorbed by the reactants to break the bonds in the reactants.

Decomposition of HgO is given by:

2HgO\rightarrow 2Hg+O_2

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What’s the two products of H2Co3
forsale [732]

Answer:

Hydrogen and Cobalt

Explanation:

Break up each individual element

- Hope that helps! Please let me know if you need further explanation.

6 0
3 years ago
PLEASEEE HELPPP I SUCK AT CHEM :(
Luda [366]

Answer:

a) H2SO4 + 2KOH -> 2H2O + K2SO4

b) 9.809 ml

Explanation:

Number of Moles = Mass/ Molar Mass

Therefore: Mass = Number of moles * Molar Mass

--------------------------------------------

Molar mass of H2SO4:

H2= 2.02

S= 32.07

O4= 64

--------------------------------------------

H2SO4 has the molar mass of 98.09

--------------------------------------------

the Moles of H2SO4 is given to be 0.100M

Therefore:

Mass= 98.09*0.1

          = 9.809g

---------------------------------------------------

Assuming that 1 g= 1 ml, the volume of sulfuric acid is 9.809 ml.

7 0
3 years ago
A 100.0 mL solution containing 0.864 g of maleic acid (MW=116.072 g/mol) is titrated with 0.276 M KOH. Calculate the pH of the s
Lilit [14]

Answer:

pH = 1.32

Explanation:

                 H₂M + KOH ------------------------ HM⁻ + H₂O + K⁺

This problem involves a weak diprotic acid which we can solve by realizing they amount  to buffer solutions.  In the first  deprotonation if all the acid is not consumed we will have an equilibrium of a wak acid and its weak conjugate base. Lets see:

So first calculate the moles reacted and produced:

n H₂M = 0.864 g/mol x 1 mol/ 116.072 g  =  0.074 mol H₂M

54 mL x  1L / 1000 mL x 0. 0.276 moles/L = 0.015 mol KOH

it is clear that the maleic acid will not be completely consumed, hence treat it as an equilibrium problem of a buffer solution.

moles H₂M left = 0.074 - 0.015 = 0.059

moles HM⁻ produced = 0.015

Using the Henderson - Hasselbach equation to solve for pH:

ph = pKₐ + log ( HM⁻/ HA) = 1.92 + log ( 0.015 / 0.059) = 1.325

Notes: In the HH equation we used the moles of the species since the volume is the same and they will cancel out in the quotient.

For polyprotic acids the second or third deprotonation contribution to the pH when there is still unreacted acid ( Maleic in this case) unreacted.

           

3 0
3 years ago
PLEASE HURRY!!!
bekas [8.4K]

Answer:

high ph -basic,low pH -acidic

Explanation:

hi I'm from India nice to meet you

5 0
3 years ago
How many atoms are in c6h4c12
Mekhanik [1.2K]

Answer:

their are a it is in the chemicle

Explanation:18 carbon and 4 hydrogen

so it is a toatle of 22 atoms

6 0
3 years ago
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