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3 years ago

NH4OH+HCLO4 Total ionic

Chemistry

1 answer:

Serggg [28]3 years ago

5 0

Answer:

$OH^-(aq)+H^+(aq)\rightarrow H_2O(l)$

Explanation:

Hello there!

In this case, according to the given reactants, it is firstly necessary to set up the complete molecular reaction:

$NH_4OH(aq)+HClO_4(aq)\rightarrow NH_4ClO_4(aq)+H_2O(l)$

Now, by knowing that ionic species are able to ionize, we are able to write the complete ionic equation:

$NH_4^++OH^-+H^++ClO_4^-\rightarrow NH_4^++ClO_4^-+H_2O(l)$

Whereas ammonium and chlorate ions are spectator ions because they remain the same on both sides of the equation. Therefore the total or net ionic equation would be:

$OH^-(aq)+H^+(aq)\rightarrow H_2O(l)$

Best regards!

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6. 100 ml of gaseous hydrocarbon consumes 300

mario62 [17]

Answer:

a. C₂H₄

Explanation:

At constant pressure and temperature, the mole ratio of the gases is equal to their volume ratio (a consequence of Avogadro's law).

Hence, the complete combustion reaction that has a ratio of 100 ml of gaseous hydrocarbon to 300 ml of oxygen, is that whose mole ratio is 1 mol hydrocarbon : 3 mol of oxygen.

Then, you must write the balanced chemical equations for the complete combustion of the four hydrocarbons in the list of choices, and conclude which has such mole ratio (1 mol hydrocarbon : 3 mol oxygen).

A complete combustion reaction of a hydrocarbon is the reaction with oxygen that produces CO₂ and H₂O, along with the release of heat and light.

a. C₂H₄:

C₂H₄ (g) + 3O₂ (g) → 2CO₂(g) + 2H₂O (g)

Precisely, for this reaction the mole ratio is 1 mol C₂H₄: 2 mol O₂, hence, this is the right choice.

The following analysis just shows that the other options are not right.

b. C₂H₂:

2C₂H₂ (g) + 5O₂ (g) → 4CO₂(g) + 2H₂O (g)

The mole ratio for this reaction is 2 mol C₂H₂ :5 mol O₂.

с. С₃Н₈

C₃H₈ (g) + 5O₂ (g) → 3CO₂(g) + 4H₂O (g)

The mole ratio is 1 mol C₃H₈ : 5 mol O₂

d. C₂H₆

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The mole ratio is 2 mol C₂H₆ : 7 mol O₂

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7. What is the voltage when the resistance is 6 ohms and the current is 8 amps?

vivado [14]

Answer:

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Explanation:

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If you have 6.25g of O2, how many moles of H2O are produced?

denis23 [38]

Answer:

0.4 moles of water produced by 6.25 g of oxygen.

Explanation:

Given data:

Mass of oxygen = 6.25 g

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Number of moles = mass/ molar mass

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