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Svetllana [295]
3 years ago
8

NH4OH+HCLO4 Total ionic

Chemistry
1 answer:
Serggg [28]3 years ago
5 0

Answer:

OH^-(aq)+H^+(aq)\rightarrow H_2O(l)

Explanation:

Hello there!

In this case, according to the given reactants, it is firstly necessary to set up the complete molecular reaction:

NH_4OH(aq)+HClO_4(aq)\rightarrow NH_4ClO_4(aq)+H_2O(l)

Now, by knowing that ionic species are able to ionize, we are able to write the complete ionic equation:

NH_4^++OH^-+H^++ClO_4^-\rightarrow NH_4^++ClO_4^-+H_2O(l)

Whereas ammonium and chlorate ions are spectator ions because they remain the same on both sides of the equation. Therefore the total or net ionic equation would be:

OH^-(aq)+H^+(aq)\rightarrow H_2O(l)

Best regards!

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When writing a formula for a compound having a transition metal in it, _____.
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Answer:

it is always necessary to use the roman numeral as the assigned charge of the metal.

Explanation:

This is so that one would know which Transition metal is being used. For example copper (II) would be Cu²+

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Find the [H+] in an acetic acid solution that has a pH of 5.12
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<span>Data:
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What is a major difference between a chemical reaction and a nuclear reaction? A) Only chemical reactions release light. B) Only
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2 years ago
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If two balls have the same volume, but ball A has twice as much mass as ball B, which one will have the greater density? ball A,
rewona [7]

Density (D) is defined as the amount or mass (m) of a substance present in a unit volume(V). It can be expressed mathematically as:

Density = Mass/Volume

i.e. D = m/V -------(1)

Units: g/cm3

a)

If m1, V1 and D1 = mass, volume  and density respectively of ball A

m2, V2 and D2 = mass, volume and density respectively of ball B

It is given that: V1 = V2; but m1 = 2m2

Based on equation (1) we have:

D1/D2 = (m1/V1)* (V2/m2) = (2m2/V2)*(V2/m2) = 2

Thus, density of ball A is twice that of B.

Ans: Ball A will have a greater density than B

b)

If m1, V1 and D1 = mass, volume  and density respectively of ball C

m2, V2 and D2 = mass, volume and density respectively of ball D

It is given that:

V1 = 3V2 and m2 = 1/3(m1) i.e m1 = 3m2

Therefore,

D1/D2 = (m1/V1)* (V2/m2) = (3m2/3V2)*(V2/m2) = 1

Thus, D1 = D2

Ans: Their densities are equal

c)

If m1, V1 and D1 = mass, volume  and density respectively of ball P

m2, V2 and D2 = mass, volume and density respectively of ball Q

It is given that:

m1 = m2 but V1 = 2V2

Therefore,

D1/D2 = (m1/V1)* (V2/m2) = (m2/2V2)*(V2/m2) = 1/2

Thus, D1 = 1/2(D2)

Ans: Ball Q will have a greater density.

d)

If m1, V1 and D1 = mass, volume  and density respectively of ball X

m2, V2 and D2 = mass, volume and density respectively of ball Y

It is given that:

V1 = 2V2 and m1 = 1/2(m2)

Therefore,

D1/D2 = (m1/V1)* (V2/m2) = ((1/2(m2)/2V2)*(V2/m2) = 1/4

Thus, D1 = 1/4(D2)

Ans: Ball Y will have a greater density.



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3 years ago
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Marysya12 [62]

Answer:

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x = 11 * 44.8 / 44.8

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