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oksian1 [2.3K]
3 years ago
10

A chemist prepares a solution of silver perchlorate by measuring out of silver perchlorate into a volumetric flask and filling t

he flask to the mark with water. Calculate the concentration in of the chemist's silver perchlorate solution. Round your answer to significant digits.
Chemistry
1 answer:
djverab [1.8K]3 years ago
7 0

Complete Question:

A chemist prepares a solution of silver (I) perchlorate (AgCIO4) by measuring out 134.g of silver (I) perchlorate into a 50.ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the silver (I) perchlorate solution. Round your answer to 2 significant digits.

Answer:

13 mol/L

Explanation:

The concentration in mol/L is the molarity of the solution and indicates how much moles have in 1 L of it. So, the molarity (M) is the number of moles (n) divided by the volume (V) in L:

M = n/V

The number of moles is the mass (m) divided by the molar mass (MM). The molar mass of silver(I) perchlorate is 207.319 g/mol, so:

n = 134/207.319

n = 0.646 mol

So, for a volume of 50 mL (0.05 L), the concentration is:

M = 0.646/0.05

M = 12.92 mol/L

Rounded to 2 significant digits, M = 13 mol/L

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CsH«N2(l) + CuCl(s)
bulgar [2K]

0.498 moles of copper(II) phthalocyanine would be produced by

the complete cyclotetramerization of 255 grams of phthalonitrile in the

presence of excess copper(ll) chloride.

<em>Copper(ll) phthalocyanine (Cu(C₃₂H₁₆N₈)) is produced by the cyclotetramerization of phthalonitrile (C₈H₄N₂) according to the following reaction: 4 C₈H₄N₂(l) + CuCl₂(s) → Cu(C₃₂H₁₆N₈)(s) + Cl₂(g) How many moles of copper(II) phthalocyanine would be produced by the complete cyclotetramerization of 255 grams of phthalonitrile in the presence of excess copper(II) chloride?</em>

Let's consider the following balanced equation.

4 C₈H₄N₂(l) + CuCl₂(s) → Cu(C₃₂H₁₆N₈)(s) + Cl₂(g)

The molar mass of C₈H₄N₂ is 128.13 g/mol. The moles corresponding to 255 g of C₈H₄N₂ are:

255 g \times \frac{1mol}{128.13 g} = 1.99 mol

The molar ratio of C₈H₄N₂ to Cu(C₃₂H₁₆N₈) is 4:1. The moles of Cu(C₃₂H₁₆N₈) produced from 1.99 moles of C₈H₄N₂ are:

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0.498 moles of copper(II) phthalocyanine would be produced by

the complete cyclotetramerization of 255 grams of phthalonitrile in the

presence of excess copper(ll) chloride.

You can learn more about stoichiometry here: brainly.com/question/22288091

8 0
2 years ago
The elementary reaction 2H2O(g)↽−−⇀2H2(g)+O2(g) proceeds at a certain temperature until the partial pressures of H2O, H2, and O2
jenyasd209 [6]

Answer:

1.742\times 10^{-5} is the value of the equilibrium constant at this temperature.

Explanation:

2H_2O\rightleftharpoons 2H_2+O_2

We are given:

Partial pressure of H_2O=p^o_{H_2O}=0.0750 atm

Partial pressure of H_2=p^o_{H_2}=0.00700 atm

Partial pressure of O_2=p^o_{O_2}=0.00200 atm

The expression of K_p for the given chemical equation is:

K_p=\frac{p^o_{H_2}^2\times p^o_{O_2}}{p^o_{H_2O}^2}

Putting values in above equation, we get:

K_p=\frac{(0.00700 atm)^2\times 0.00200 atm}{(0.0750 atm)^2}\\\\K_p=1.742\times 10^{-5}

1.742\times 10^{-5} is the value of the equilibrium constant at this temperature.

3 0
4 years ago
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