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Luba_88 [7]
2 years ago
8

114. The following equation describes the oxidation of ethanol to acetic acid by potassium permanganate!

Chemistry
1 answer:
alukav5142 [94]2 years ago
7 0

Answer:

Explanation:

The following equation describes the oxidation of ethanol to aceticacid by potassium permanganate:

3C2H5OH +4KMnO4-->3HC2H3O2 +4MnO2 + 4KOH + H2O

5.0 g of ethanol and an excess of aqueous KMnO4 arereacted, and 5.9 g HC2H3O2 result.What is the percent yield?

a. 100%

b. 91%

c. 67%

d. 30%

e. 5.9 g HC2H3O2 is impossible since it represcents more than a100% yield.

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3 years ago
How can we make use of acids or bases to Prevent the growth of microorganisms in swimming pools?
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By putting smarticle particles 
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3 years ago
What is the density of a liquid if it's volume is 125 mL and it's mass is 50g?
masha68 [24]

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0.4g/ml

Explanation:

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6 0
2 years ago
Given the balanced equation below, calculate the moles of aluminum that are needed to react completely with 28.7 moles of FeO. Y
Alexxx [7]

Answer:

43.05 moles of Al needed to react with 28.7 moles of FeO.

Explanation:

Given data:

Moles of FeO = 28.7 mol

Moles of Al needed to react with FeO = ?

Solution:

Chemical equation:

2Al + 3FeO → 3Fe + Al₂O₃

Now we will compare the moles of Al with FeO.

                            FeO        :           Al

                             2            :            3

                          28.7          :         3/2×28.7 = 43.05 mol

Thus 43.05 moles of Al needed to react with 28.7 moles of FeO.

8 0
3 years ago
How many grams of CO₂ can be produced from the combustion of 2.76 moles of butane according to this equation: 2 C₄H₁₀(g) + 13 O₂
Vilka [71]

Answer:

485.76 g of CO₂ can be made by this combustion

Explanation:

Combustion reaction:

2 C₄H₁₀(g) + 13 O₂ (g) → 8 CO₂ (g) + 10 H₂O (g)

If we only have the amount of butane, we assume the oxygen is the excess reagent.

Ratio is 2:8. Let's make a rule of three:

2 moles of butane can produce 8 moles of dioxide

Therefore, 2.76 moles of butane must produce (2.76 . 8)/ 2 = 11.04 moles of CO₂

We convert the moles to mass → 11.04 mol . 44g / 1 mol = 485.76 g

5 0
3 years ago
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