How many moles is 5.70x10^23 molecules of NH3?
1 answer:
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Explanation:
The given data is as follows.
Flow of chlorine (Q) =
Amount of liter present per day is as follows.
It is given that dosage of chlorine will be as follows.
10 mg/l = kg/l
Therefore, total chlorine requirement is as follows.
Total chlorine requirement = kg/day
= 100 kg/day
Thus, we can conclude that the kilograms of chlorine used daily at the given water treatment plant is 100 kg/day.