Need HELP! OA:point U OB:point V OC:point W OD: point X

Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74

lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0

3 years ago

3 over 3 - square root 5

DIA [1.3K]

Answer:

-1.236.

Step-by-step explanation:

3/3 = 1.

√5 = 2.236.

1.000 - 2.236 = -1.236.

the answer is negative because the smaller number is subtracting the larger number..........u just subtract the normal way,( the larger number take away the smaller number), but u should insert a negative sign to the answer.

5 0

3 years ago

How would I do this at the bottom it says solution

Jlenok [28]

Answer:

all you have to do is graph them but put them in y=mx+b form first, the coordinates is the solution

4 0

3 years ago

Jeff is selling hamburgers and pizza at the tailgate party. The cost of 4

Sphinxa [80]

Answer:

Step-by-step explanation

4 0

2 years ago

Read 2 more answers

Describe the end behavior of a 14th degree polynomial with a positive leading coefficient.

kipiarov [429]

The function will enter the graph graph in the upper left hand region and exit in the upper right hand region and overall the graph will be concave upwards.
For determining the end behavior of a polynomial, there is just 2 things to take notice of.
1. Is the leading coefficient positive or negative?
2. Is the degree of the polynomial odd or even?
For odd ordered polynomials, the curve starts in either quadrant II or III, and ends in quadrant IV, or I. Basically, if it's positive, the curve enters the graph somewhere in the lower left hand region, and exits the graph in the upper right hand region. If the coefficient is negative, it enters in the upper left hand region, and exits in the lower right hand region.
For even ordered polynomials, the graph is either concave upwards (positive leading coefficient) or concave downwards (negative leading coefficient).
In this problem, 14 is an even number and since the coefficient is positive, the function will enter the graph graph in the upper left hand region and exit in the upper right hand region and overall the graph will be concave upwards.

4 0

3 years ago

Need HELP! OA:point UOB:point VOC:point WOD: point X​

Need HELP! OA:point UOB:point VOC:point WOD: point X