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SashulF [63]
3 years ago
13

What is the theoretical yield of Li3N in grams when 12.7 g of Li is heated with 34.7 g of N2

Chemistry
1 answer:
Nata [24]3 years ago
3 0
<span>12.7 g Li*(1 mole Li/6.94 g Li)=1.83 moles of Li
34.7 g N2(1 mole N2/28 g N2)=1.23
1.83 moles Li*(2 moles Li3N/6 mole Li)(34.82 grams Li3N/1 mole Li3N)=21.24g Li3N </span>
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A bicycle tire is filled with air to a pressure of 100. psi at a temperature of 19C. Riding the bike on asphalt on a hot day inc
Zigmanuir [339]

Considering the direct relationship between pressure and temperature, the new pressure in the bicycle tire would be 63.01 psi

<h3>Gas law</h3>

The general gas laws is given by:

  P1V1/T1 = P2V2/T2

Where P1 = initial pressure V1 = initial volume T1 = initial temperature, P2 = final pressure, V2 = final volume, and T2 = final temperature.

In this case, P1 = 100 psi, V1 = 1, T1 = 19+273 = 292, P2 = ?, V2 = 1.4, T2 = 58+273 = 331

P2 = P1V1T2/T1V2

        = 100x1x292/331x1.4

                   = 63.01 psi

More on gas laws can be found here: brainly.com/question/1190311

5 0
2 years ago
The reaction can be described using the equation: 2C2H25O24CO22H2O. How much C2H2is needed to react with 68.1 g of O2to produce
Sophie [7]

Answer:

22.13g

Explanation:

We'll begin by writing a balanced equation for the reaction. This is illustrated below:

2C2H2 + 5O2 —> 4CO2 + 2H2O

Next, we'll calculate the mass of C2H2 and O2 that reacted from the balanced equation. This is illustrated below:

Molar Mass of C2H2 = (12x2) + (2x1)

= 24 + 2 = 26g/mol

Mass of C2H2 that reacted from the balanced equation = 2 x 26 = 52g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 that reacted from the balanced equation = 5 x 32 = 160g

Now, we can obtain the mass of C2H2 that will react with 68.1g of O2 as follow:

From the balanced equation above,

52g of C2H2 reacted with 160g of O2.

Therefore, Xg of C2H2 will react with 68.1g of O2 i.e

Xg of C2H2 = (52x68.1)/160

Xg of C2H2 = 22.13g

Therefore, 22.13g of C2H2 is needed to react with 68.1g of O2

8 0
3 years ago
a car is traveling at a speed of 55 mph the speed increased to 75 mph if the time needed to hange its speed is 4 seconds whats t
Savatey [412]

v = 75 mph = 33.52 m/s

u = 55 mph = 24.58 m/s

t = 4 sec

acceleration = v-u/t

= 33.52-24.58/4

= 8.94/4

= 2.235 m/s

6 0
3 years ago
Who is the father of genetics​
-BARSIC- [3]
Gregor Mendel

Hope this helped !
6 0
3 years ago
Read 2 more answers
What mass in grams of SO2 is needed to react with 37.50 mol of Oz?
-BARSIC- [3]

Answer:

4804.5 g of SO₂ are needed to the reaction

Explanation:

The reaction to produce sulfuric acid is:

2SO₂ + O₂ + 2H₂O →  2H₂SO₄

Ratio is 1:2. 1 mol of oxygen needs 2 moles of sulfur dioxide in order to react. We can propose this rule of three.

If 1 mol of O₂ react to 2 moles of SO₂

Then, 37.50 moles of O₂ will react with (37.5 . 2) /1 = 75 moles of SO₂

We convert the moles to mass, to know the answer:

75 mol . 64.06 g / 1 mol = 4804.5 g of SO₂

6 0
3 years ago
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