What is the theoretical yield of Li3N in grams when 12.7 g of Li is heated with 34.7 g of N2

1 answer:

3 0

<span>12.7 g Li*(1 mole Li/6.94 g Li)=1.83 moles of Li
34.7 g N2(1 mole N2/28 g N2)=1.23
1.83 moles Li*(2 moles Li3N/6 mole Li)(34.82 grams Li3N/1 mole Li3N)=21.24g Li3N </span>

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