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MrRissso [65]
3 years ago
8

Given f(x)= 1/3(4-x)^2, what is the value of f(16)

Mathematics
2 answers:
vampirchik [111]3 years ago
8 0

Answer:

48

Step-by-step explanation:

f(x)= 1/3(4 - x)^2

f(16) = (1/3)(4 - 16)^2

f(16) = (1/3)(-12)^2

f(16) = (1/3)(144)

f(16) = 48

Fofino [41]3 years ago
6 0

The value of f(16) is 48.

Solve: f(x)=1/3(4-x)^2,

 

Solution:  

1. Write the equation

f(x)= 1/3(4 - x)^2

2. Substitute 16 into the x

f(16) = (1/3)(4 - 16)^2

3. Simplify

f(16) = (1/3)(144)

4. Multiply

f(16) = 48

Therefore, the value of f(16) is 48.

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