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beks73 [17]
3 years ago
13

The speed of sound through diamond is about 12,000 m/s. The speed of sound through wood is about 3,300 m/s. Which statement expl

ains why the speed of sound is different through these materials?(1 point)
They have different rigidities.

They have different temperatures.

They have different phases of matter.

They have different salinities.
Physics
1 answer:
iris [78.8K]3 years ago
3 0

Answer: They have different rigidities.

Explanation:

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Answer plz also give reason
user100 [1]

See this suggested solution.

1. Let a force F' is the vector sum of the forces P and Q, then it is shown on the attached picture and marked with red color.

2. according to the condition the force F holds the object, then F should have the same length as the force F' and the opposite direction.

3. using the conditions described in 2. the answer is C.

4 0
3 years ago
The candle burning
vodka [1.7K]

Answer:

A

Explanation:

its oxygen I hope i am correct have a great day.

3 0
3 years ago
A rocket of mass 40000kg propelled by a force of 10^6N acquires a speed of 3000m/s determine the power expended
Katyanochek1 [597]

Answer:

3×10⁹ W

Explanation:

Power = work / time

Power = force × distance / time

Power = force × velocity

P = Fv

P = (10⁶ N) (3000 m/s)

P = 3×10⁹ W

6 0
3 years ago
An object has a mass of 50.0 g and a volume of 10.5 cm3. What is the object's density?
vagabundo [1.1K]
The density is 4.76 gcm^-3
and if mass is in kg then density is equal to 4.76*10^-3
3 0
3 years ago
Read 2 more answers
A multimeter in an RL circuit records an rms current of 0.600 A and a 50.0-Hz rms generator voltage of 110 V. A wattmeter shows
jeka57 [31]

Answer:

(a) The impedance in the circuit is Z=183.33\Omega.

(b)The resistance is R=38.89\Omega.

(c) The inuctance is 0.57 H.

Explanation:

(a)

The expression for the impedance is as follows:

Z=\frac{V_rms}{I_rms}

Here, V_rms is the rms voltage and I_rms is the rms current.

PutV_rms=110 V and I_rms=0.600 A.

Z=\frac{110}{0.600}

Z=183.33\Omega

Therefore, the impedance in the circuit is Z=183.33\Omega.

(b)

The expression for the average power is as follows;

P_{a}=I_{rms}^{2}R

Here, P_{a} is the average power and R is the resistance.

Calculate the resistance by rearranging the above expression.

R=\frac{P_{a}}{I_{rms}^{2}}

Put P_{a}=14W and

R=\frac{14}{{0.600}^{2}}

R=38.89\Omega

Therefore, the resistance is R=38.89\Omega.

(c)

The expression for the impedance is as follows;

Z^{2}=R^{2}+X_{L}^{2}

Here,X_{L} is the inductive reactance.

Put Z=183.33\Omega and R=38.89\Omega.

(183.33)^{2}=(38.89)^{2}+X_{L}^{2}

X_{L}=179.16\Omega

The expression for the inductive reactance in terms of  frequency is as follows;

X_{L}=2\pi fL

Here, L is the inductance.

Calculate the inductance by rearranging the above expression.

L=\frac{X_{L}}{2\pi f}

Put X_{L}=179.16\Omega and f=50Hz.

L=\frac{179.16}{2\pi (50)}

L=0.57 H

Therefore, the inuctance is 0.57 H.

4 0
3 years ago
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