Answer:
v = 7.18_m/s
Explanation:
Velocity of the earth towards the ball is = velocity of the ball moving towards earth
For object in free fall, we have
Where
v = final velocity
u = initial velocity
g = acceleration due to gravity
t = time
S = height of ball above ground
v^2 = u^2 - 2×g×(-S)
= 0 + 2×9.8×2.63 = 51.55_m^2/s^2
Velocity of the ball just before it hits the ground is
v = 7.18_m/s
Answer: A
After rocks are eroded the particles turn into a sedimentary rock.
<h3>Answer</h3>
option B)
19N
<h3>Explanation</h3>
If the object is at equilibrium, then the net force acting upon the object should be 0 N. Thus, if all the forces are added together, horizontal and vertical forces separately, then the resultant force (the vector sum) should be 0 Newton.
As we only need to find the magnitude of x-component of force F
so find all x component/horizontal forces acting on the object.
50cos(40) - 40cos(25) + 30cos(55) + x = 0
38.30 - 36.25 + 17.21 + x + = 0
19.26 + x = 0
x = - 19.26
x ≈ 19 (magnitude only)
Mass = 1.2 kg = 1200 grams.
Volume = mass/density = 1200 cm3.
Hope this helps!
