Answer:
Given
mᴀ = mʙ = mᴄ = 62 kg
Fᴀ = 480N
Fʙ = 240 N
Fᴄ = 600 N
Asked
aᴀ, aʙ, aᴄ = ?
Solution
Based on the question, we know that the mass of road A, road B and road C are same. And, the formula of acceleration is
so, we can calculate the acceleration of road A, road B and road C.
• for road A
aᴀ = 7,7419 m/s²
aᴀ = 7,75 m/s²
• for road B
aʙ = 3,8709 m/s²
aʙ = 3,87 m/s²
• for road C
aᴄ = 9,6774 m/s²
aᴄ = 9,68 m/s²
Explanation:
Answer: w = 200N
Explanation:
w = mg
m = 20kg
g = 10m/s^ (approximately)
w = 20kg . 10m/s^
w = 200N
The first one would be frequency. Here’s what I found to support that “The number of waves passing a fixed point in a certain amount of time is called the The word frequent means “often,” so frequency measures how often a wave occurs. Frequency is often measured by counting the number of crests or troughs that pass by a given point in one second”
The second one would be a medium “Mechanical waves require a medium in order to transport their energy from one location to another. “
Answer:
a. 6
b. 6 m/s²
c. 300 m to the right
d. 30 secs
Explanation:
slope = rise /run
60-0/10-0
= 6
b. slope = acceleration = 6 m/s²
c. d=ut+1/2at²
t=10 (segment A last for 10 secs)
u - initial velocity = 0
so d = 0(10)+1/2*6*10²
=300 m
