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alexandr402 [8]
3 years ago
13

To keep with the law of conservation of matter, determine the correct product for the following reaction:

Physics
2 answers:
Charra [1.4K]3 years ago
6 0

Answer: Answer is ( B ) on usa test prep

Explanation:

user100 [1]3 years ago
4 0

Answer:

B) PbI2 + 2 KCl

Explanation:

To keep the the law of conservation of matter, the equation given above must be balanced i.e the total element in the reactant must be equal to the total elements in the product.

Given the equation

PbCl2 (aq) + 2 KI (aq) →

At the reactant shown, there are one mole of lead Pb, 2 moles of chlorine Cl, 2moles of Potassium K and 2 moles of Iodine.

During reaction, the Chlorine atom will react with the potassium atom K and the lead atom Pb will react with the iodine atom.

The resulting product that will balance the chemical equation is

PbI2 + 2 KCl

The equation will then become

PbCl2 (aq) + 2 KI (aq) → PbI2 + 2 KCl

If we look at both sides of the equation, we will see that all the elements have the same number of atoms.

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Answer:

7.65x10^3 m/s

Explanation:

The computation of the satellite's orbital speed is shown below:

Given that

Earth mass, M_e = 5.97 × 10^24 kg

Gravitational constant, G = 6.67 × 10^-11 N·m^2/kg

Orbital radius, r = 6.80 × 10^6m

Based on the above information

the satellite's orbital speed is

V_o = √GM_e ÷ √r

= √6.67 × 10^-11 × 5.97 × 10^24 ÷ √6.80 × 10^6

=  7.65x10^3 m/s

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3 years ago
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Answer:

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Explanation:

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HeLp aSAp!!! If the speed and distance of an object are given, and I need to find the time, I will...
Helen [10]

Answer:

B - Divide Speed and Distance

Explanation:

Hope it helps!!

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5 0
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Answer:

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butalik [34]

Answer:

<em>D. The acceleration after it leaves the hand is 10 m/s/s downwards </em>

Explanation:

<u>Vertical Throw </u>

When an object is thrown upwards, it describes a special type of motion ruled only by gravity.  

When the ball is launched, it has its maximum speed upwards. The acceleration of gravity is always the same because it's a constant value near our planet's surface. The object starts to lose speed since the acceleration of gravity is pointed downwards and makes the object stop in the mid-air at its maximum height, where the speed is zero. Then, the object starts to fall and regain speed, this time downwards until it reaches back the launching point at the very same speed it was launched, but in the opposite direction.

The time it takes to reach its maximum height is the same it takes to return to the catching point, 2 seconds later.  

With all these concepts in mind, we state that:

<em>D. The acceleration after it leaves the hand is 10 m/s/s downwards  </em>

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2 years ago
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