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3 years ago

16 En un juego de béisbol, un lanzador logra

Physics

1 answer:

Anuta_ua [19.1K]3 years ago

5 0

Answer:

B transferida.

Explanation:

The kinetic energy of the baseball would be transferred to the bat and to the handler.

The law of conservation of energy states that "energy is neither created nor destroyed but transformed from one form to another".

We know that the baseball posses kinetic energy as it begins to accelerate towards the other player.
Kinetic energy is the energy due to the motion of a body.
As it collides with the bat, it is converted to another form of energy.
The energy form would have been converted to kinetic energy, heat energy and some mechanical energy component.
Therefore, the energy has been transferred from the ball to the bat.

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(URGENT) A ball rolls off a ledge. Its velocity is 7.70m/s in a horizontal direction. It falls on the floor 1.60m below the ledg

elena-s [515]

Answer:

the horizontal distance is 4.355 meters

Explanation:

The computation of the horizontal distance while travelling in the air is shown below:

Data provided in the question is as follows

Velocity = u = 7.70 m/s

H = 1.60 m

R = horizontal direction

Based on the above information

As we know that

R = u × time

where,

Time = $\sqrt{\frac{2H}{g} }$

So,

= $7.70\times \sqrt{\frac{2\times 1.60}{10} }$

= 4.355 meters

hence, the horizontal distance is 4.355 meters

6 0

3 years ago

an object of mass m is traveling at constant speed v in a circular path of radius r. how much work is done by the centripetal fo

vlada-n [284]

The work done is by the centripetal force on mass m during an angular displacement of 2π revolutions mv²2π /r J

Centripetal force - a force acts on an moving object in circular path.

the centripetal force is given by

F= mv²/r (equation1)

Work done is given by

W = Fd (equation 2)

d = 2π

work is done by the centripetal force on mass m during an angular displacement of 2π revolutions is given by:

to calculate work done using equation 1 in 2 we get

W = mv² d/r

W = mv² × 2π /r J

The work done is by the centripetal force on mass m during an angular displacement of 2π revolutions mv²2π /r J

To know more about centripetal force :

brainly.com/question/13031430

#SPJ4

6 0

1 year ago

A 90.0 kg man climbs hand over hand up a rope to a height of 9.47 m. How much potential energy does he have at the top?

kati45 [8]

Answer:

8361.063 J

Explanation:

7 0

2 years ago

All pressure topics in physics

AfilCa [17]

Absolute, Atmospheric, Differential, and Gauge Pressure

5 0

2 years ago

For each of the following pairs of gas properties, describe the relationship between the properties, describe a simple system th

asambeis [7]

Answer:

For each pair of properties of a gas, the relationships are (see the explanation for the description of the systems):

(a) Volume and pressure: The relationship between them is inversely proportional.
(b) Pressure and temperature: They have a directly proportional relationship.
(c) Volume and temperature: They relationship is directly proportional.
(d) Number of gas particles and pressure: The relationship is directly proportional between them.

Explanation:

1. Volume and pressure (temperature and amount of particles constant):

They have an inversely proportional relationship, because if volume is reduced, the pressure increases, or if the volume increases, the pressure decreases.

A simple system could be one similar to the one used by Boyle to test this relationship:

Seal the short extreme of a translucent J tube. It could be glass or plastic.
Put some water on it. As much as needed to have both sides of the tube filled.
Using a syringe, and a flexible small tube,inject a determined volume of air in the bottom in a way that the bubble is trapped in the seal side of the J tube.
Then if more water is added to the tube, it will increase the pressure (from the pressure definition is possible to in the trapped air, and is possible to measure the compression of the air bubble. The same is possible if using the syringe, and the flexible tube, some water is removed, and the increasing of volume could be observed.

2. Pressure and temperature (volume and amount of particles of the gas remains constant)

They have a directly proportional relationship, because if temperature is reduced, the pressure decreases, or if the temperature increases, the pressure would increase, also.

A simple system to show this is two cans of soda.

The can is rigid, so the volume is always constant, and the amount of gas inside the soda is the same.
Put one can under the sun, and the other in the cooler.
After a while, take it out the can in the cooler, and open both cans.
The one that was under the sun will "explode", in other words, it will liberate a lot of foam of gas and soda, meaning that the pressure inside the can was high.
The one that was in te cooler, won't liberate any foam, meaning that the pressure was low.

3. Volume and temperature (pressure and amount of particles of the gas remains constant)

They have a directly proportional relationship, because if temperature is reduced, the pressure decreases, or if the temperature increases, the pressure will increase, also.

A simple system to show this is a party balloon.

Fill the party balloon with some air, not enough to be close to explode, but enough to have it of a medium size. Tie the filling hole of the balloon.

The air inside the balloon would be at the same pressure than the atmosphere around it, so always will be at this pressure, and the close hole ensure that it has always the same amount of air inside.

Now is possible to use some heat source, for example as a hair dryer to increase the temperature of the balloon and its contents. The size of the balloon will increase. Then using water is possible to cool it down and watch how its size decreases.

4. Number of gas particles and pressure (volume and temperature of gas remains constant)

They have a directly proportional relationship, because if the amount of gas particles is reduced, the pressure decreases, or if quantity of gas particles increases, the pressure will increase, also.

A simple system to show this would be a bicycle tire:

The tire is rigid, so its volume is essentially constant, and the temperature would remains the same if not moving or driving it.

Using a tire gauge, it is possible to know the manometric pressure inside the tire, that is the difference between the actual pressure inside the tire and the atmospheric pressure.

Then each time that using an air pump some air is injected in the tire, it si possible to check the pressure inside it using the gauge, and observe how is increasing.

Also, is possible to open the valve, to allow some air to escape, then use the gauge to observe how the pressure decreases.

7 0

3 years ago