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motikmotik
3 years ago
8

A boy of 50 kg jumps off a boat (30 kg), causing the boat to move to the right at 2.0 m/s. In what direction and at what velocit

y does the boy move? (Remember to include - to indicate direction if necessary.)
V=____ m/s to the _____
Physics
2 answers:
LUCKY_DIMON [66]3 years ago
8 0
By Newtons Third law this is an action reaction pair of force
So the momentum is the same
30*20=50*x where x is velocity
x= 12m/s
direction is towards left since they act in opposite directions
andrew11 [14]3 years ago
5 0

Answer: The boy moves with velocity = <u>1.2 m/s</u> to the <u>left</u>.

Explanation:

<u>From law of conservation momentum, when there is no net external force acting on the system, the momentum remains conserved.</u>

⇒M u + m u' = M v + m v'

M is the mass of boy = 50 kg

u is its initial velocity = 0

m is the mass of the boat, m = 30 kg

u' is the initial speed of the boat, = 0

v is the final velocity of the boy

v' is the final velocity of the boat = +2.0 m/s

we would consider positive direction towards and negative towards left.

⇒ 0 = 50 v + 30 × 2

⇒ -50 v = 60

⇒ v = - 1.2 m/s (negative sign indicates towards left)

Thus, the boy moves with velocity = <u>1.2 m/s</u> to the <u>left</u>.

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