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3 years ago

Is there is only one tool used to heat equipment in the laboratory.

Physics

2 answers:

yaroslaw [1]3 years ago

7 0

This is false there are many tools used to heat equipment in the laboratory such as a Fuel burner.

Dafna1 [17]3 years ago

6 0

No there is not only one tool used. They are many. Examples are:

Buchner funnel
Bunsen burner
Buret.

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What is the gravitational potential energy of a 150 kg object suspended 5m above the Earth's surface

ella [17]

The gravitational potential energy referred to the ground level is given by
$U=mgh$
where m is the mass of the object, $g=9.81 m/s^2$ is the gravitational acceleration and h is the height of the object with respect to the ground.

Therefore in our problem the potential energy is
$U=(150 kg)(9.81 m/s^2)(5 m)=7357.5 J$

6 0

3 years ago

How does the mass of a bowling ball that has been rolled down the lane affect the kinetic energy?

solniwko [45]

The heavier it is the more frictions it creates sliding on the floor. this make more kinetic energy.

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2 years ago

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Calculate the wavelength in centimeters of radar energy at a frequency of 10 GHz. What is the frequency in gigahertz of radar en

ddd [48]

Answer:

Energy will be equal to $6.6\times 10^{-27}J$

Frequency will be equal to $12\times 10^8Hz$

Explanation:

We have given frequency of the radar f = 10 GHz $=10\times 10^6Hz$

Speed of light $c=3\times 10^8m/sec$

Plank's constant $h=6.6\times 10^{-34}js$

So energy $E=h\nu$ ,here h is plank's constant and $\nu$ is frequency

So energy $E=6.6\times 10^{-34}\times 10^{7}=6.6\times 10^{-27}J$

In second case we have given wavelength = 25 cm = 0.25 m

Wavelength is equal to $\lambda =\frac{c}{f}$

So $f=\frac{c}{\lambda }=\frac{3\times 10^8}{0.25}=12\times 10^8Hz$

So frequency will be equal to $12\times 10^8Hz$

8 0

2 years ago

What are the three subatomic particles of an atom?

Anestetic [448]

Protons, neutrons, and electrons are the three main subatomic particles found in an atom. Protons have apositive (+) charge. An easy way to remember this is to remember that both proton and positive start with theletter "P." Neutrons have no electrical charge.

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2 years ago

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Refer to Concept Simulation 4.4 for background relating to this problem. The drawing shows a large cube (mass = 28.9 kg) being a

Usimov [2.4K]

Answer:

smallest magnitud is P=33.3 N

Explanation:

We are analyze the situation as an external force is applied and there is a friction force. We have a problem with Newton's second law.

F = ma

As the two blocks go together they must have the same acceleration, so we can calculate this for the entire system

P = (m1 + m2) a

a = P / (m1 + m2)

In this case there is no friction force because the small block does not touch the ground.

In order to calculate the friction force, we must analyze each system component separately.

The large block on the X axis has an applied P force and as it moves feels a force from the small block. In the Y axis has the weight (W1) and the reaction to normal (N1)

For the small block on the X axis, the force it feels is the thrust of the large block, note that this is an action and reaction force between the two blocks, it is the same definition we have of the normal one, so we can call this force (N)

Y axis it has the weight (W2) down, the force of friction (fr) that opposes the movement, so it is directed upwards. we write these equations

N = m2 a

fr -W2 = 0

fr = W2

The definition of friction force is

fr = μ N

Let's replace and calculate

μ (m2 a) = m2 g

μ (P / (m1 + m2)) = g

P = g /μ (m1 + m2)

Let's calculate the value of this force

P = 9.8 / 0.710 (28.9 +4.4)

P = 13.80 (33.3)

P = 33.3 N

This is the minimum friction force that prevents the block from sliding down

6 0

2 years ago