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Nata [24]
3 years ago
7

Tech A says that an overdrive gear ratio means the input gear turns faster than the output gear. Tech B says that overdrive rati

os provide less torque output than underdrive ratios. Who is correct?
Physics
1 answer:
Kazeer [188]3 years ago
6 0

Answer:

Technician B only is correct

Explanation:

The gear ratio is the ratio of the output speed to the input speed such that an overdrive gear ratio of more than 1:1, having more speed per speed of engine rotation RPM

Overdrive ratios conditions is one where the vehicle wheels and speed is faster at a given engine rotation, such that there is fuel efficiency is increased as the engine rotation is low for a given speed and distance of travel.

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Which statement describes the density of the inner planets?
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The inner planets are less dense than the outer planets

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Why wil an ice cube melt if it is compressed even if it remains at the same temp
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No, it will only melt if the temperature is lowered. If you compress it, it will change the shape, but it will not change the state it is in (i.e. solid).
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Which type of drug would be useful in dilating the pupils for an examination of the retina? Which type of drug would be useful i
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muscarinic receptor inhibitor

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Read 2 more answers
The orbits of most comets
Ludmilka [50]

Answer:

option B

Explanation:

The correct answer is option B

Comets are the frozen snowball that is made of different gases and which rotates around the sun.

Comets are generally icy but when comets come near to the sum they get warm and release gasses which can be seen from the earth.

Comet produces a visible atmosphere or coma.

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The orbit of comets is entirely beyond the orbit of Neptune.

4 0
3 years ago
A race car starts from rest on a circular track of radius 378 m. The car's speed increases at the constant rate of 0.580 m/s2. A
insens350 [35]

Answer:

a) V=14.904m/s

b) d = 191.49 m

c) t= 25.696 s

Explanation:

From the question we are told that:

Radius r =378m

Acceleration a=0.580

a)

Generally the  equation for speed of the car is mathematically given by

 a=\frac{v^2}{r}

 V=\sqrt{a*r}

 V=\sqrt{0.58*383}

 V=14.904m/s

b)

Generally the  equation for distance traveled of the car is mathematically given by

 V^2=u^2+2ad

 d=\frac{V^2}{2a}

 d=\frac{14.904^2}{2*0.58}  

 d = 191.49 m

c)

Generally the  equation for time of the car is mathematically given by

 V=u+at

 t=\frac{V}{a}

 t=\frac{14.904}{0.58}

 t= 25.696 s

3 0
3 years ago
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