Answer:
480 g of oxygen.
Explanation:
C3H8 + 5O2 ---> 3CO2 + 4H2O
Using the molar masses:
3*12 + 6*16 g of CO2 were formed from 10*16 g O2
132g g CO2 from 160 g O2
1g CO2 from (160/132) g O2
396 g from (160/132) * 396
= 480 g of oxygen.
Answer:
The final volume should be 22 mL
Explanation:
For this problem, we will use the dilution equation:
C1*V1 = C2*V2
<u>Step 1</u>: Data given
with C1 = the initial concentration C1 = 0.220 mg/L
with V1 = the initial volume = 10 mL = 10 * 10^-3 L
with C2 = the final concentration = 0.100 mg/L
with V2 = the final volume = TO BE DETERMINED
<u>Step 2</u>: Calculating the final volume
C1*V1 = C2*V2
0.220 mg/L * 10*10^-3 L = 0.100 mg/L * V2
V2 = (0.220 mg/L * 10*10^-3 L) / 0.100 mg/L
V2 =0.022 L = 22 mL
The final volume should be 22 mL
Answer:
There will be a critical shortage. -In garden, water plants early in the morning or in the evening.
