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max2010maxim [7]
4 years ago
8

Help ASAP!

Chemistry
1 answer:
ipn [44]4 years ago
5 0

I believe the answer is D

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Water ionizes by the equationH2O(l)⇌H+(aq)+OH−(aq)The extent of the reaction is small in pure water and dilute aqueous solutions
tia_tia [17]

Explanation:

H_2O(l)\rightleftharpoons H^+(aq)+OH^-(aq)

The value of K_w :

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a. pOH = 3.51

The sum of pH and pOH is equal to 14.

pH + pOH = 14 (at 25°C)

pH = 14 - 3.51 = 10.49

The pH of the solution is defined as negative logarithm of hydrogen ion concentration in solution.

pH=-\log[H^+]

10.49=-\log[H^+]

[H^+]=3.2\times 10^{-11}

3.2\times 10^{-11} Mis the H^+ concentration for an aqueous solution with pOH = 3.51 at 25°C.

b.

At a certain temperature, the pH of a neutral solution is 7.56.

Neutral solution means that concentration of hydrogen ion and hydroxide ions are equal.

[H^+]=[OH^-]

7.56=-\log[H^+]

[H^+]=2.754\times 10^{-8} M

The value of K_w at at this temperature:

K_w=[H^+][OH^-]

K_w=[H^+][H^+]

K_w=(2.754\times 10^{-8})^2=7.6\times 10^{-16}

The value of K_w at at this temperature is 7.6\times 10^{-16}.

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