Answer: yes they are
Explanation:
because its so hot and the heat just stays at the bottom
The final gas pressure : 175.53 atm
<h3>Further explanation</h3>
Maybe the complete question is like this :
A ridged steel tank filled with 62.7 l of nitrogen gas at 85.0 atm and 19 °C is heated to 330 °C while the volume remains constant. what is the final gas pressure?
The volume remains constant⇒Gay Lussac's Law
<em>When the volume is not changed, the gas pressure in the tube is proportional to its absolute temperature </em>
![\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7BP_1%7D%7BT_1%7D%3D%5Cdfrac%7BP_2%7D%7BT_2%7D)
P₁=85 atm
T₁=19+273=292 K
T₂=330+273=603 K
![\tt P_2=\dfrac{P_1\times T_2}{T_1}\\\\P_2=\dfrac{85\times 603}{292}\\\\P_2=175.53~atm](https://tex.z-dn.net/?f=%5Ctt%20P_2%3D%5Cdfrac%7BP_1%5Ctimes%20T_2%7D%7BT_1%7D%5C%5C%5C%5CP_2%3D%5Cdfrac%7B85%5Ctimes%20603%7D%7B292%7D%5C%5C%5C%5CP_2%3D175.53~atm)
Answer:
The coloring and possibly testing it
<em>Balance</em> <em>Chemical equation:</em>
- C4H6O6 + 2NaOH ⇒ Na2C4H4O6 + 2H2O
<em>Given Data:</em>
Molarity of NaOH =0.3000
Vol. of NaOH = 21.65
<em>Solution:</em>
moles of NaOH = (0.3000 × 21.65)÷1000 = 0.0064 mol
According to balance chemical equation
NaOH : C4H6O6
2 : 1
0.0064 = (1/2) ×0.0064 = 0.0032 mol
So these 0.0032 mol of tartaric acid are prsent in 50.0 ml of solution.
So in I littre of solutions, its concentration will be as follow
M = 0.0032 × 1000/50 = 0.064 M
<em>Result: </em>
- The concentration of acid will be 0.064 M.