Explanation: Solution
1.
Gravitational potential energy
U=mgh=500*9.8*50
U=245000 J
2.
Kinetic energy is present at bottom of the hill
K=(1/2)mV2=(1/2)*500*27.82
K=193210 J
3.
Work done by friction
W=193210-245000=-51790 J
Answer:
a)
n=sin i/sin r
n= -0.305/-0.428
n=0.713
b)
sin c=1/n
sin c=1/0.713
sin c= 1.403
c=sin⁻¹(1.403)
c= 40.842°
Explanation:
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Answer:
1
2
3
Explanation:
From the question we are told that
The speed of the car is 
The length of the ramp is 
The constant velocity of the traffic 
Generally the acceleration of the car is mathematically represented as
Here u is equal to zero given that the car started from rest so
=>
Generally the time taken is mathematically represented as
=> 
=>
The distance traveled by the traffic is mathematically represented as
Here a is zero given that the traffic was moving at constant speed
=> 
=>
according to newton's second law , net force on an object is the product of mass of the object and the acceleration of the object. the formula is given as
F = ma where F = net force , m = mass and a = acceleration
so acceleration can be given as
a = F/m
for same net force , the acceleration depends on the mass of the object .
greater the mass , smaller will be the acceleration and vice versa.
Since the mass of electron is smaller as compared to the mass of proton, hence the electron will accelerate more as compared to proton.
A) The electron will accelerate more than the proton
Answer:
4.167
Explanation:
ittravels 4.167metres per second
