Answer:
Explanation:
vertical magnetic field B_v = 4 x 10⁻⁵ T.
Magnetic field due to horizontal current at point 20 cm above
= (μ₀/4π ) x (2i / R)
= 10⁻⁷ x 2 x 20/ 20 x 10⁻²
= 2 x 10⁻⁵ T
It will act coming out of paper. Hence it will be normal to magnetic field given .
So resultant magnetic field
= √ (4² + 2²) x 10⁻⁵ T
= 4.47 X 10⁻⁵ T .
Question three is C and question 4 is b
Answer:
Temperature on Jupiter and Saturn are too high for methane to condense.
Explanation:
However, methane can condense on Uranus and Neptune because they are farther from the sun and hence colder.
The starting angle θθ of a pendulum does not affect its period for θ<<1θ<<1. At higher angles, however, the period TT increases with increasing θθ.
The relation between TT and θθ can be derived by solving the equation of motion of the simple pendulum (from F=ma)
−gsinθ=lθ¨−gainθ=lθ¨
For small angles, θ≪1,θ≪1, and hence sinθ≈θsinθ≈θ. Hence,
θ¨=−glθθ¨=−glθ
This second-order differential equation can be solved to get θ=θ0cos(ωt),ω=gl−−√θ=θ0cos(ωt),ω=gl. The period is thus T=2πω=2πlg−−√T=2πω=2πlg, which is independent of the starting angle θ0θ0.
For large angles, however, the above derivation is invalid. Without going into the derivation, the general expression of the period is T=2πlg−−√(1+θ2016+...)T=2πlg(1+θ0216+...). At large angles, the θ2016θ0216 term starts to grow big and cause
