A 500 kg car is at rest at the top of a 72 m high hill. The car rolls to the bottom of the hill. At the bottom of the hill, the
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The sample's density with respect to the volume it displaces is equal to: C. 0. 60 g/mL
<u>Given the following data:</u>
- Mass = 1.8 grams
- Initial volume = 20 mL
- Final volume = 23 mL
To calculate the sample's density:
First of all, we would determine the volume displaced by the sample;
Volume displaced = 3 mL
Density can be defined as mass all over the volume of an object. Thus, density is mass per unit volume of an object.
Mathematically, the density of a substance is given by the formula;
Substituting the given parameters into the formula, we have;
Density = 0.60 g/mL
Read more: brainly.com/question/18320053
Answer:
A. 7.1m
B. 3.55m/s
C. 1.775m/s^2
Explanation:
First step is to identify given parameters;
Ball 1: m₁ = 0.5kg, u (initial velocity) =0, t = 2seconds
Ball 2: m₂ = 0.25kg, u = 15m/s, t = 2seconds
<u>Second step:</u> we determine the y-coordinate of ball 1 after 2 seconds, using the equation of motion under gravity as shown below;
Recall, that the ball was thrown from a height of 25m, total y-coordinate of ball 1 after 2 seconds becomes 25m +(-19.6m)
[tex]y_{1} = 5.4m[/tex]
<u>Third step</u>: we determine the y-coordinate of ball 2 after 2 seconds
<u>Fourth step: </u>we determine the y-component of the center mass of the two balls
y = 7.1m
<u>Fifth step:</u> we solve B part of the question; velocity of the center mass of the two balls
velocity = 3.55m/s
<u>Sixth step:</u> we solve C part of the question; acceleration of the center mass of the two balls
acceleration = 1.775 m/s^2