Answer: The nuclide symbol of X is 
Explanation:
The given nuclear reaction is a type of alpha decay process. In this process, the nucleus decays by releasing an alpha particle. The mass number of the nucleus is reduced by 4 units and atomic number is also decreased by 2 units. The particle released is a helium nucleus.
The general equation representing alpha decay process is:

For the given equation :

As the atomic number and mass number must be equal on both sides of the nuclear equation:

Thus the nuclide symbol of X is 
Answer: Option (d) is the correct answer.
Explanation:
A reaction in which there occurs change in oxidation state of reacting species is known as an oxidation-reduction reaction.
(a)
Will be written as:

In this reaction, there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.
(b) 
Will be written as:

Similarly here, there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.
(c) 
Will be written as:

Here, also there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.
(d) 
So, here there occurs change in oxidation state of Mg from 0 to +2 and oxidation state of H changes from +1 to 0. Hence, it is an oxidation-reduction reaction.
Thus, we can conclude that
is an oxidation-reduction reaction.
Answer:
B. ribosome
Explanation:
In the ribosomes, the codons get paired with anti codons to create a polypeptide or protein.
Answer:
152 kPa = Partial pressure O₂
Explanation:
Data by percent is the molar fraction . 100.
Molar fraction of Helium = 32/ 100 → 0.32
Molar fraction of O₂ = 68/100 → 0.68
Sum of molar fractions in a mixture = 1
0.68 + 0.32 = 1
If we apply the molar fraction, we can determine the partial pressure.
Mole fraction = Partial pressure / Total pressure
0.32 = Partial pressure O₂ / 475kPa → 0.32 . 475 kPa = Partial pressure O₂
152 kPa = Partial pressure O₂