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Leokris [45]
3 years ago
9

Trends in atomic radius of Period 3 elements

Chemistry
1 answer:
serious [3.7K]3 years ago
5 0

Answer:

Here's what I find  

Explanation:

A. Period or Group?

Na Mg Al Si

These elements are in Period 3.

B. Trend in atomic radius

\begin{array}{ccc}\textbf{Atom} &\textbf{At. No.} &\textbf{r/nm }\\\text{Na} & 11& 0.19 \\\text{Mg} & 12 & 0.14 \\\text{Al} & 13 & 0.12 \\\text{Si} & 14 & 0.11 \\\end{array}

The graph below shows that the atomic radius decreases as the atomic number increases, that is, as you go from left to right across the Period.

C. Explanation

As you go from left to right across a Period, you are adding electrons to the n = 3 shell. The electrons repel each other, so the atoms tend to increase in size.

However, you are also adding protons to the nucleus, so the attraction between the protons and the electrons increases. Each added electron can shield only about 0.3 of a proton's charge, so the nuclear attraction wins out and the atomic radius decreases.

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Calculate the mass in grams of 2.56 × 10 −3 mol of iron.
gizmo_the_mogwai [7]

Answer:

1.43 grams

Explanation:

Fe = 55.8 grams Fe = 1 mole Fe

2.56 • 10^-3 moles Fe / 1 • 55.8 grams Fe / 1 mole Fe = 1.43 grams Fe

Basically, you're just multiplying the molar mass of Fe (iron) by the moles of 2.56 • 10^-3 Fe, to find how many grams are in it.

2.56 • 10^-3 moles Fe = 1.43 grams Fe

5 0
3 years ago
An iron object alloyed with cobalt rusts more quickly than a pure iron object. However, an iron object alloyed with manganese ru
HACTEHA [7]

Rusting is an electrochemical reaction. Iron rusts faster when alloyed with cobalt than when alloyed with manganese because, in the iron-manganese alloy, manganese is rendered the anode and iron is rendered the cathode

An alloy is a combination of two metals. There are various reasons for producing alloys such as greater tensile strength, corrosion resistance and improved aesthetic appearance.

When iron is alloyed with cobalt, the iron rusts faster than pure iron because iron is rendered the anode and cobalt is rendered the cathode. When the iron is alloyed with manganese, it rusts more slowly than pure iron because in the iron-manganese alloy, manganese is rendered the anode and iron is rendered the cathode.

Missing parts;

An iron object alloyed with cobalt rusts more quickly than a pure iron object. However, an iron object alloyed with manganese rusts less quickly than a pure iron object under the same conditions. This is true because

(1) cobalt is a stronger reducing agent than iron

(2) iron is a stronger reducing agent than manganese

(3) cobalt exhibits more metallic character than either iron or manganese

(4) in the iron-manganese alloy, manganese is rendered the anode and iron is rendered the cathode

(5) in the iron-cobalt alloy, cobalt is rendered the anode and iron is rendered the cathode

Learn more: brainly.com/question/14281129

5 0
3 years ago
To draw a complete lewis structure of one molecule of water, how many electrons must be shown?
love history [14]
In the Lewis structure, each single bond drawn between elements contain two electrons. The electron dots represent the lone pairs. These are the electrons that take part in the reaction. To obey the octet rule, the oxygen must have eight electrons around it. The hydrogen is exempted from this rule. Therefore, you have to show two electrons.

5 0
3 years ago
Read 2 more answers
Which of the following is an example of an energy transformation?
erica [24]

Answer:

D

Explanation:

8 0
3 years ago
How many moles of helium are needed to fill a balloon to a volume of 5.3 L at 22 ℃ and 632 mmHg?
son4ous [18]

Answer:

0.18 moles

Explanation:

Applying,

PV = nRT................... Equation 1

Where P = pressure, V = volume, n = number of moles, R = molar gas constant, T = temperature.

make n the subject of the equation

n = PV/RT............... Equation 2

Given: V = 5.3 L, T = 22 °C = (22+272) K = 295 K, P = 632 mmHg = (0.00131579×632) = 0.8316 atm,  R = 0.083 L.atm/K.mol

Substitute these values into equation 2

n = (0.8316×5.3)/(0.083×295)

n = 0.18 moles

6 0
3 years ago
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