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Leokris [45]
3 years ago
9

Trends in atomic radius of Period 3 elements

Chemistry
1 answer:
serious [3.7K]3 years ago
5 0

Answer:

Here's what I find  

Explanation:

A. Period or Group?

Na Mg Al Si

These elements are in Period 3.

B. Trend in atomic radius

\begin{array}{ccc}\textbf{Atom} &\textbf{At. No.} &\textbf{r/nm }\\\text{Na} & 11& 0.19 \\\text{Mg} & 12 & 0.14 \\\text{Al} & 13 & 0.12 \\\text{Si} & 14 & 0.11 \\\end{array}

The graph below shows that the atomic radius decreases as the atomic number increases, that is, as you go from left to right across the Period.

C. Explanation

As you go from left to right across a Period, you are adding electrons to the n = 3 shell. The electrons repel each other, so the atoms tend to increase in size.

However, you are also adding protons to the nucleus, so the attraction between the protons and the electrons increases. Each added electron can shield only about 0.3 of a proton's charge, so the nuclear attraction wins out and the atomic radius decreases.

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Melting of ice is a spontaneous reaction at room temperature and pressure because melting is accompanied by _____.
ki77a [65]

Answer:

An increase in entropy

Explanation:

In ice, the molecules are very well ordered because of the H-bonds. As ice melts, the intermolecular forces are broken (requires energy), but the order is interrupted (so entropy increases). Water is more random than ice, so ice spontaneously melts at room temperature.

Just think about this rationally. Melting ice (or anything) will require heat put in (this is called the latent heat of fusion), so you automatically know that the change in enthalpy is going to be positive. In order to make the reaction spontaneous, delta G, the Gibbs free energy has to be negative. So now look at the formula Delta(G) = Delta(H) - T*Delta*(S). If you know that g is negative, and H is positive, then it is only possible if -T*Delta(S) is negative. If that is positive, then Delta(S) has to be positive. So theres your answer :). An increase in entropy

4 0
4 years ago
During the reaction of 2,4-dinitrofluorobenzene with methoxide in methanol it was observed that it occurs at a significantly hig
Pachacha [2.7K]

Answer:

Explanation:

your not so smart

3 0
3 years ago
What is the ph of a solution that is 0.50 m in propanoic acid and 0.40 m in sodium propanoate. (ka for propanoic acid = 1.3 x 10
max2010maxim [7]
<span>The pH is given by the Henderson - Hasselbalch equation:
              pH = pKa + log([A-]/[HA])
              pH = -log(</span><span>1.3 x 10^-5) + log(0.50/0.40)
              pH = 4.98
The answer to this question is 4.98.
</span>
3 0
4 years ago
Explain what happens to the average kinetic energy thermal energy and temperature of a substance when the particles in the subst
kkurt [141]
The average kinetic energy and thermal energy decreases, and the temperature decreases as well.
8 0
3 years ago
Read 2 more answers
What volume of carbon dioxide, at 1 atm pressure and 112°C, will be produced when 80.0 grams of methane is burned?
Vadim26 [7]

Answer:

158 L.

Explanation:

What is given?

Pressure (P) = 1 atm.

Temperature (T) = 112 °C + 273 = 385 K.

Mass of methane CH4 (g) = 80.0 g.

Molar mass of methane CH4 = 16 g/mol.

R constant = 0.0821 L*atm/mol*K.

What do we need? Volume (V).

Step-by-step solution:

To solve this problem, we have to use ideal gas law: the ideal gas law is a single equation which relates the pressure, volume, temperature, and number of moles of an ideal gas. The formula is:

PV=nRT.

Where P is pressure, V is volume, n is the number of moles, R is the constant and T is temperature.

So, let's find the number of moles that are in 80.0 g of methane using its molar mass. This conversion is:

80.0g\text{ CH}_4\cdot\frac{1\text{ mol CH}_4}{16\text{ g CH}_4}=5\text{ moles CH}_4.

So, in this case, n=5.

Now, let's solve for 'V' and replace the given values in the ideal gas law equation:

V=\frac{nRT}{P}=\frac{5\text{ moles }\cdot0.0821\frac{L\cdot atm}{mol\cdot K}\cdot385K}{1\text{ atm}}=158.04\text{ L}\approx158\text{ L.}

The volume would be 158 L.

6 0
1 year ago
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