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2 years ago

7

Please help i dont get it

1 answer:

raketka [301]2 years ago

6 0

<em>x</em> and <em>w</em> are parallel lines, so

• angles 2 and the one labeled 75º are congruent because they are alternating interior angles, and

• angles 1 and 2 are supplementary because they form a linear pair.

The first observation tells you that angle 2 has measure 75º, and angle 1 has measure <em>m</em> such that

<em>m</em> + 75º = 180º

so angle 1 has measure 180º - 75º = 105º.

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Jesse owes $8,473 on a credit card with a 21.5% interest rate. What is the monthly payment he should make to pay off this debt i

kakasveta [241]

You can use an online credit card calculator in computing the monthly payment. Refer to the attachment for the answer and graph. The given are the following: balance - 8,473; interest rate - 21.5%; months - 12. The answer is the third option - you'll need to pay <span>$790.99 every month for 12 months.</span>

3 0

2 years ago

Group of friends are going to see a movie. The admission cost is $8 per person. The table below represents the number of friends

vagabundo [1.1K]

Answer:

B) (2, 16), (3, 24), (4, 32), (5, 40)

Step-by-step explanation:

1 ticket costs $8. 8 x 2 = 16, so 2 tickets cost $16. 8 x 3 = 24, so 3 tickets cost $24. The same thing goes for 4 tickets, and 5 tickets.

4 0

2 years ago

Read 2 more answers

Explain the steps you would take to write 36/10 as a decimal

kherson [118]

You just have to make 36/10 into 3 6/10. After that, it would become 3.6

4 0

2 years ago

Read 2 more answers

Solve the following equation:

Rama09 [41]

Complete the square.

$z^4 + z^2 - i\sqrt 3 = \left(z^2 + \dfrac12\right)^2 - \dfrac14 - i\sqrt3 = 0$

$\left(z^2 + \dfrac12\right)^2 = \dfrac{1 + 4\sqrt3\,i}4$

Use de Moivre's theorem to compute the square roots of the right side.

$w = \dfrac{1 + 4\sqrt3\,i}4 = \dfrac74 \exp\left(i \tan^{-1}(4\sqrt3)\right)$

$\implies w^{1/2} = \pm \dfrac{\sqrt7}2 \exp\left(\dfrac i2 \tan^{-1}(4\sqrt3)\right) = \pm \dfrac{2+\sqrt3\,i}2$

Now, taking square roots on both sides, we have

$z^2 + \dfrac12 = \pm w^{1/2}$

$z^2 = \dfrac{1+\sqrt3\,i}2 \text{ or } z^2 = -\dfrac{3+\sqrt3\,i}2$

Use de Moivre's theorem again to take square roots on both sides.

$w_1 = \dfrac{1+\sqrt3\,i}2 = \exp\left(i\dfrac\pi3\right)$

$\implies z = {w_1}^{1/2} = \pm \exp\left(i\dfrac\pi6\right) = \boxed{\pm \dfrac{\sqrt3 + i}2}$

$w_2 = -\dfrac{3+\sqrt3\,i}2 = \sqrt3 \, \exp\left(-i \dfrac{5\pi}6\right)$

$\implies z = {w_2}^{1/2} = \boxed{\pm \sqrt[4]{3} \, \exp\left(-i\dfrac{5\pi}{12}\right)}$

3 0

1 year ago

The RANGE of the function is

forsale [732]

Answer:

Range is [1, ∞)

Step-by-step explanation:

The values of x can be 1 up to infinity (the domain).

When x = 1 , f(x) = 1^2 = 1

when x = ∞, x^2 = ∞

So the range is [1, ∞)

5 0

2 years ago