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iren2701 [21]
2 years ago
10

What is the quotient of 2x^3 +3x^2+5x-4 divided by x^2 + x+ 1

Mathematics
2 answers:
Alexus [3.1K]2 years ago
8 0

Answer:

2x^3+3x^2+6x-4/x^2 +1

Step-by-step explanation:

wlad13 [49]2 years ago
8 0

Answer:

2*x+1+\frac{2*x-5}{x^2+x+1}

Step-by-step explanation:

Where, the quotient is 2·x + 1, and the reminder is 2·x - 5

Hence, the above is correct is as follows:

The given dividend is 2·x³ + 3·x² + 5·x - 4

The divisor is x² + x + 1

By long division of a polynomial we have;

2·x + 1 [Quotient]

(2·x³ + 3·x² + 5·x - 4) ÷ (x² + x + 1 )

2·x³ + 2·x² + 2·x

0    +   x²  + 3·x - 4

          x² + x    + 1

          0  + 2·x - 5

Thurs, we have:

\frac{(2*x^3 + 3*x^2 + 5*x - 4)}{x^2+x+1} =2*x+1+\frac{2*x-5}{x^2+x+1}

Hence, the correct answer is 2*x+1+\frac{2*x-5}{x^2+x+1}  

[RevyBreeze]

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