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swat32
3 years ago
5

NEED HELP

Physics
1 answer:
aniked [119]3 years ago
5 0

Answer:

I = 0.25 [amp]

Explanation:

To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the current by the resistance.

V = I*R

where:

V = voltage [Volt]

I = amperage or current [amp]

R = resistance [ohm]

Since all resistors are connected in series, the total resistance will be equal to the arithmetic sum of all resistors.

Rt = 2 + 8 + 14

Rt = 24 [ohm]

Now clearing I for amperage

I = V/Rt

I = 6/24

I = 0.25 [amp].

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Explanation:

Use <u>v1</u><u>/</u><u>T1</u><u>=</u><u>v2</u><u>/</u><u>T2</u>

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3 years ago
Shanti is riding on a train that is moving at a speed of 90 km/h. He is carrying a power cord for his phone that is 1.2 m long.
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Answer:equal to 1.2 m

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Find the radioactivity of a 1 g sample of 226Ra given that <img src="https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D1620" id="TexFormul
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6 0
3 years ago
A force of 10. N toward the right is exerted on a wooden crate initially moving to the right on a horizontal wooden floor. the c
Artyom0805 [142]

1) 5 N

The crate is initially moving, so we must calculate the force of kinetic friction, which is given by:

F_f = \mu_k mg

where

\mu_k=0.2 is the coefficient of friction between the crate (made of wood) and the floor (made of wood). The coefficient of kinetic friction between wood and wood is about 0.2.

mg=25 N is the weight of the crate

Substituting the numbers into the formula, we find

F_f=(0.2)(25 N)=5 N


2) 5 N

There are two forces acting on the crate along the horizontal direction:

- The force that pushes the crate toward the right, of magnitude F=10 N

- The force of friction, which acts in the opposite direction (so, towards the left), of magnitude F_f = 5 N

Since the two forces are in opposite directions, the net force is given by their difference:

F_{net}=F-F_f = 10 N-5 N=5 N


3) Yes

The crate is accelerating. In fact, according to Second Newton's Law:

F_{net}=ma (1)

where Fnet is the net force on the crate, m is its mass, a is its acceleration. We can immediately see that since Fnet is not zero, the acceleration is also non-zero, so the crate is accelerating.

We can even calculate the magnitude of the acceleration. In fact, the mass of the crate is given by:

m=\frac{Weight}{g}=\frac{25 N}{9.8 m/s^2}=2.55 kg

And by using (1) we find

a=\frac{F_{net}}{m}=\frac{5 N}{2.55 kg}=1.96 m/s^2


3 0
3 years ago
An object has a total kinetic energy of 2,400,000 J. If it’s mass is 0.004 kg, then what is it’s velocity.
VladimirAG [237]
I dont know let me check
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