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3 years ago

Help me with these 2 questions

Mathematics

2 answers:

Anettt [7]3 years ago

6 0

1. Exact form: 17/4
Mixed number: 4 1/4
2. Exact form: 372/35
Mixed number: 10 22/35

almond37 [142]3 years ago

4 0

Answer:

1. 4¼

2. 10 22/35

Step-by-step explanation:

First, find a common denominator, in this case number 1 would contain a common denominator of 4, and for number 2 it could be 35 (7 x 5 = 35).

Then create an equivalent fraction, 1/2 turned into fourths would be 2/4. 2/4 + 3/4 = 5/4, which equals 1 1/4. Then add 1 1/14 + 1 + 2 = 4¼

For number 2, 3/7 = 15/35 and 1/5 = 7/35. Add them and get 22/35, then add the other numbers. 4 + 6 + 22/35 = 10 22/35

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<h3>How to determine the length ac?</h3>

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MrRa [10]

your question is incomplete, here you can find the complete question below:

An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the varying radian measure of the angle.

a. if the terminal ray of the angle passes through the point(3.38,2.32), whta is the slope of the terminal ray of the angle?

b. if the terminal ray of the angle passes through the point(1.49,3.82), whta is the slope of the terminal ray of the angle?

c. if the terminal ray of the angle passes through the point(1.1,3.95), what is the slope of the terminal ray of the angle?

Answer:

a. 1.45

b. 2.56

c. 3.59

Step-by-step explanation:

As we know that formula to find the slope is change in y-coordinates divided by change in x-coordinates.

$slope=\frac{chnage\ in\ y}{chnage\ in\ x}=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

It is given that initial point is (x1,y1)=(0,0)

Part(a)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(3.38,2.32)

so the slope of the terminal ray is

$slope=\frac{3.38-0}{2.32-0}=\frac{3.38}{2.32}= 1.45$

Part(b)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.49,3.82)

so the slope of the terminal ray is

$slope=\frac{3.82-0}{1.49-0}=\frac{3.82}{1.49}=2.56$

Part(c)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.1,3.95)

so the slope of the terminal ray is

$slpoe=\frac{3.95-0}{1.1-0}=\frac{3.95}{1.1}= 3.59$

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