Question

Is there anyone good at algebra 2 to solve this problem? I need help with part c.

Answer 1

Answer:

40 ft

Step-by-step explanation:

The maximum height of the ball is the y- coordinate of the vertex

Given a parabola in standard form then the x- coordinate of the vertex is

$x_{vertex}$ = - $\frac{b}{2a}$

h(t) = - 16t² + 48t + 4 ← is in standard form

with a = - 16, b = 48 , thus

$x_{vertex}$ = - $\frac{48}{-32}$ = 1.5

Substitute t = 1.5 into h(t) for max. height

h(1.5) = - 16(1.5)² + 48(1.5) + 4

         = - 36 + 72 + 4

          = 40