1 ? 2 transverse 3 longitudinal
Answer:
Explanation:
<u>The total momentum of a system is defined by:</u>
Where,
is the total momentum or it could be expressed also as 
.
and 
represents the masses of the objects interacting in the system.
and 
are the velocities of the objects of the system.
<em>Remember: </em><em>The momentum is a fundamental physical magnitude of vector type.</em>
We have:
We are going to take the east side as positive, and the west side as negative. Then the velocity of the car B, has to be <u>negative</u>. It goes in a different direction from car A.
Then the total momentum of the system is:
Answer:
A. 1.172 metres
B. 6.82 Ns
C. 4.796 m/s
Explanation:
The total initial momentum is gotten by multiplying the mass and initial velocity of the both bodies.
The 1.40 kg block is at rest so velocity is zero and has no momentum.
The bullet of mass 22 g = 0.022 kg with velocity of 310 m/s
Momentum = 310*0.022
Momentum = 6.82 Ns.
If the bullet gets embedded they will both have common velocity v
6.82 = (0.022+1.40)v
6.82 = 1.422v
V = 6.82/1.422
V = 4.796 m/s
How high the block will rise after the bullet is embedded is given by
H = (U²Sin²tita)/2g
Where tita is 90°
H = (4.796² * sin²(90))/(2*9.81)
H =( 23.001616*1)/19.62
H = 1.172 metres
Answer:
To the nearest integer, the penny's speed in m/s be right as it reaches the ground if it was dropped from rest = 91 m/s
Explanation:
We have equation of motion
S = ut + 0.5at²
Here u = 0, a = g and t = 9.3 s
We have equation of motion v = u +at
Substituting
v = u +at
v = 0 + 9.8 x 9.3 = 91.14 m/s
To the nearest integer, the penny's speed in m/s be right as it reaches the ground if it was dropped from rest = 91 m/s
