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Crank
3 years ago
8

What happens in a cold front? A.A cold air mass catches up to a moving warm air mass, sliding over it. B.A warm air mass becomes

a cold air mass as it moves. C.A warm air mass collides with a stationary cold air mass, and slides under it. D.A cold air mass comes in under a warm air mass.
Physics
2 answers:
svlad2 [7]3 years ago
6 0

Answer:

A cold air mass comes in under a warm air  mass

Explanation:

Sav [38]3 years ago
4 0
In meteorology (the study of weather), a "front" is the leading edge
of an air mass, that's moving in and replacing a mass of a different
kind of air.  Like warm moving in and replacing cold, or cold moving
in and replacing warm.

Remember that cold air is heavier than warm air.  So whenever a
warm or cold front moves in, the cold air always stays low and the 
warm air always lifts up over it.

With that little bit of an explanation, you can see that choice-D is
the only choice that makes sense.
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A wedge with a mechanical advantage of 0.78 is used to raise a house corner from its foundation. If the output force is 7500 N,
Zigmanuir [339]

Answer:

5850

Explanation:

MA = Force out/ Force in

.78 = out/ 7500

.78 times 7500 = input

6 0
3 years ago
An electrical power plant manages to send 88% of the heat produced in the burning of fossil fuel into the water-to-steam convers
Naya [18.7K]

Answer:

A

Explanation:

Let the x represent the amount of heat generated from the fossil fuel.

88% of x = 0.88 x

0.88 x was used to convert water to steam.

heat carried by steam = 40% × 0.88 x = 0.352 x

efficiency of the heat -to- work conversion = work output / work input = 0.352 x / x = 0.352 × 100 = 35.2 % which is less than 40 %

4 0
3 years ago
The operating temperature of a tungsten filament in an incandescent light bulb is 2450 K, and its emissivity is 0.350. Find the
natulia [17]

Answer:

The value is   A =  2.80 *10^{-4} \  m^2

Explanation:

From the question we are told that

The  operating temperature is  T  =  2450 \  K

The emissivity is  e =  0.350

 The  power rating is  P  =  200 \  W

Generally the area is mathematically represented as

      A = \frac{P}{ e *  \sigma  *  T^2}

Where  \sigma is the Stefan Boltzmann constant  with value  

      \sigma  =  5.67 *10^{-8} \  W/m^2\cdot K^4

So

     A =  \frac{200}{0.350 *  5.67*10^{-8} *  2450^{4}}

     A =  2.80 *10^{-4} \  m^2

8 0
3 years ago
Given:A=6x-2y B:-4x-8y C:-3x+9y. Commute A+B-C
DedPeter [7]
<span>A+B-C
</span><span>A = 6x - 2y
B = -4x - 8y
C = -3x + 9y

(</span>6x - 2y) + (-4x - 8y) - (-3x + 9y)
(6x - 2y) + (-4x - 8y) + (3x - 9y)
2x -10y + (3x - 9y)

5x - 19y
8 0
3 years ago
Infrared light of wavelength 2.5 µm illuminates a 0.20-mm-diameter hole. What is the angle of the first dark fringe in radians?
stepan [7]

Answer:

Θ=0.01525 rad

or

Θ=0.87°

Explanation:

Given data

wavelength λ=2.5 µm =2.5×10⁻⁶m

Diameter d=0.20 mm =0.20×10⁻³m

To find

Angle Θ in radians and degree

Solution

Circular apertures have first dark fringe at

Θ=(1.22λ)/d

Substitute the given values

So

Θ=[1.22(2.5×10⁻⁶m)]/0.20×10⁻³m

Θ=0.01525 rad

or

Θ=0.87°

6 0
3 years ago
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