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Crank
3 years ago
8

What happens in a cold front? A.A cold air mass catches up to a moving warm air mass, sliding over it. B.A warm air mass becomes

a cold air mass as it moves. C.A warm air mass collides with a stationary cold air mass, and slides under it. D.A cold air mass comes in under a warm air mass.
Physics
2 answers:
svlad2 [7]3 years ago
6 0

Answer:

A cold air mass comes in under a warm air  mass

Explanation:

Sav [38]3 years ago
4 0
In meteorology (the study of weather), a "front" is the leading edge
of an air mass, that's moving in and replacing a mass of a different
kind of air.  Like warm moving in and replacing cold, or cold moving
in and replacing warm.

Remember that cold air is heavier than warm air.  So whenever a
warm or cold front moves in, the cold air always stays low and the 
warm air always lifts up over it.

With that little bit of an explanation, you can see that choice-D is
the only choice that makes sense.
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vovangra [49]

Answer:

Explanation:

electric field at the location of electron

= 9 x 10⁹ x 7.2 / .03²

= 72 x 10¹² N/C

force on electron = electric field x charge on electron

= 72 x 10¹² x 1.6 x 10⁻¹⁹

= 115.2 x 10⁻⁷ N .

C )

work done = charge on electron x potential difference at two points

potential at .03 m

= 9 x 10⁹ x 7.2 / .03

= 2.16 x 10¹² V

potential at .001 m

= 9 x 10⁹ x 7.2 / .001

= 64.8 x 10¹² V

potential difference = (64.8 - 2.16 )x 10¹² V

= 62.64 x 10¹² V  .

work done = 62.64 x 10¹² x 1.6 x 10⁻¹⁹

= 100.224 x 10⁻⁷ J .

D )

There will be no change in the magnitude of force on positron except that the direction of force will be reversed . In case of electron , there will be repulsion and in case of positron , there will be attraction .

Work done in case of electron will be positive and work done in case of positron will be negative .

electric field due to charge will be same in both the cases .

8 0
2 years ago
Beginning<br> lonic compounds are made up of a__<br> and a__
Romashka-Z-Leto [24]

Answer:

metal and non-metal

Explanation:

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3 0
3 years ago
Read 2 more answers
Determine how many times per second it would move back and forth across a 6.0-m-long room on the average, assuming it made very
timofeeve [1]

Answer:

The right solution is "24.39 per sec".

Explanation:

According to the question,

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The time will be:

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hence,

⇒ N=\frac{1}{t}

        =\frac{1}{0.041}

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sergeinik [125]

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6 0
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